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sec x=2 is it the solution?
i wish it was that easy but its not :'( the answer has multiple solutions
tan(x)*sec(x) - 2*tan(x) = 0 tan(x)*[ sec(x) - 2 ] = 0 tan(x) = 0 or sec(x) - 2 = 0 tan(x) = 0 or sec(x) = 2 tan(x) = 0 or 1/cos(x) = 2 tan(x) = 0 or cos(x) = 1/2 I'll let you finish up
the kpi solution is for sin x=0 and the other two ae for sec x=2
it's been a while since I've done this but you have to be in radian mode and add or subtract 2pi or something
depends on the quadrant you're in as well .
they made a typo they should have 2k*pi and not just 2k
when you wrote `0+kpi ` `2kpi + pi/3` `2kpi + 5pi/3` you have all 3 correct
5pi/3 is coterminal to -pi/3, so either works
so judging on which one is the closest... it'd be A?
you'll have to bring it up with your teacher so they can fix it
but yeah A looks closest
i will thanks jim you da bestttttttttttttttt
when you solve it, you get sin x=0 and sec x=2 so you get the answer as given