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Bananas1234
 one year ago
Simplify and identify the domain.
5/5x + 15 times 2(x + 2)/x^2  4
Bananas1234
 one year ago
Simplify and identify the domain. 5/5x + 15 times 2(x + 2)/x^2  4

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rajat97
 one year ago
Best ResponseYou've already chosen the best response.0to identify the domain, we need to see at which points, the function is undefined so the function is undefined at three points. those points are 3,2 and 2 the function is defined and exists at all real numbers except these three. thus the domain is all real numbers except 3,2,2

rajat97
 one year ago
Best ResponseYou've already chosen the best response.0hello Bananas1234 is it right??

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1I think everyone needs a mandatory course in latex or something. I can't read this.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1rajat, you're right for 2,2, and 3 will make the denominator 0. assuming that this is the right equation.

Bananas1234
 one year ago
Best ResponseYou've already chosen the best response.0idk what latex is. and i agree with the 2, 2 and 3 but what about the simplify part?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0factor both denominators, then cancel common terms

rajat97
 one year ago
Best ResponseYou've already chosen the best response.0look at the denominators

rajat97
 one year ago
Best ResponseYou've already chosen the best response.0the numbers at which the denominators become zero are the numbers that will be excluded from the domain

Bananas1234
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433046092010:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.15/5x + 15 times 2(x + 2)/x^2  4 \[\frac{5}{5x+15} \times \frac{2(x+2)}{x^24}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1if we can pull that 5 out on the first denominator and then make sure that \[x^24 = (x+2)(x2) \] omg latex come on. x^24 = (x+2)(x2) cancel out some of the terms... you should be able to cancel out 2 of them

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1sorry my end is bugged... need to refresh

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{5}{5(x+3)} \times \frac{2(x+2)}{(x+2)(x2)}\] do you see anything that needs to be canceled out?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1the common terms are 5 and x+2... since I can see them on the numerator and denominator we can cancel it out.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{(x+3)} \times \frac{2}{(x2)}\] and since we're not dealing with addition, we can just multiply this through. \[\frac{2}{(x+3)(x2)}\]
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