Simplify and identify the domain. -5/5x + 15 times 2(x + 2)/x^2 - 4

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Simplify and identify the domain. -5/5x + 15 times 2(x + 2)/x^2 - 4

Mathematics
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to identify the domain, we need to see at which points, the function is undefined so the function is undefined at three points. those points are -3,2 and -2 the function is defined and exists at all real numbers except these three. thus the domain is all real numbers except -3,-2,2
hello Bananas1234 is it right??
I think everyone needs a mandatory course in latex or something. I can't read this.

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rajat, you're right for -2,2, and -3 will make the denominator 0. assuming that this is the right equation.
idk what latex is. and i agree with the -2, 2 and -3 but what about the simplify part?
factor both denominators, then cancel common terms
look at the denominators
the numbers at which the denominators become zero are the numbers that will be excluded from the domain
|dw:1433046092010:dw|
-5/5x + 15 times 2(x + 2)/x^2 - 4 \[\frac{-5}{5x+15} \times \frac{2(x+2)}{x^2-4}\]
if we can pull that 5 out on the first denominator and then make sure that \[x^2-4 = (x+2)(x-2) \] omg latex come on. x^2-4 = (x+2)(x-2) cancel out some of the terms... you should be able to cancel out 2 of them
sorry my end is bugged... need to refresh
\[\frac{-5}{5(x+3)} \times \frac{2(x+2)}{(x+2)(x-2)}\] do you see anything that needs to be canceled out?
the common terms are 5 and x+2... since I can see them on the numerator and denominator we can cancel it out.
\[\frac{-1}{(x+3)} \times \frac{2}{(x-2)}\] and since we're not dealing with addition, we can just multiply this through. \[\frac{-2}{(x+3)(x-2)}\]
Thanks

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