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is3535

  • one year ago

Andrew estimated the weight of his dog to be 60 lb. The dog’s actual weight was 68 lb. What was the percent error in Andrew’s estimate? Round your answer to the nearest tenth of a percent.

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  1. is3535
    • one year ago
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    i think 12 or 11.7

  2. is3535
    • one year ago
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    @sammixboo

  3. is3535
    • one year ago
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    @Vocaloid

  4. is3535
    • one year ago
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    @butterflydreamer

  5. is3535
    • one year ago
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    @ro561man

  6. rajat97
    • one year ago
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    is it 11.76?

  7. is3535
    • one year ago
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    i think 12 or 11.7

  8. butterflydreamer
    • one year ago
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    11.76 is correct :) If we were to round it, it would become 11.8 :)

  9. dan815
    • one year ago
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    wrong

  10. is3535
    • one year ago
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    so 11.8 is my answerr

  11. anonymous
    • one year ago
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    divide it bye .10

  12. rajat97
    • one year ago
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    the qualified helper says its wrong

  13. butterflydreamer
    • one year ago
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    yes, that's correct

  14. is3535
    • one year ago
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    ther not smart the qualified helper

  15. rajat97
    • one year ago
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    i'll be back in some time

  16. anonymous
    • one year ago
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    i get 680

  17. dan815
    • one year ago
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    BRUH

  18. butterflydreamer
    • one year ago
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    LOL... um. I think what you need to do is first find the difference (error) between your estimated weight and the actual weight. So 60 - 68 = -8 Ignore the negative... so our error is 8. Then to find the percentage error we do : error/ actual value = 8 / 68 = 2/17 Then change it into a percentage by multiplying by 100. 2/17 * 100 = 11.76 Then round it to the nearest tenth ( 1 decimal point) 11.76 = 11. 8 (1dp)

  19. anonymous
    • one year ago
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    oh that makes since lol

  20. butterflydreamer
    • one year ago
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    .......................................................... http://prntscr.com/7bd9ro

  21. butterflydreamer
    • one year ago
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    sooooooooooo 11.8% is correct if you follow the steps above/ use the formula above :)

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