- Bananas1234

Simplify. u^2-4/u^2 - 2u

- schrodinger

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- nikato

|dw:1433048410396:dw|
is this your question?

- anonymous

you can factorize u^2-4 to (u-2)(u+2)
and next exp as u(u-2)
cancel out (u-2) from denom and num

- Bananas1234

u + 2, u is not 2?

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## More answers

- UsukiDoll

we have a perfect square on the numerator... can we split that up in the form of (a+b)(a-b) where a = x and b =2?!

- Bananas1234

i dont think so, can we?

- UsukiDoll

whatttttttttttttttttttt! pop quiz what the square root of 4

- Bananas1234

2

- UsukiDoll

yes... whenever we have a perfect square we can split (a^2-b^2) in the form of (a+b)(a-b)

- UsukiDoll

so since a = x and b = 2 what is the numerator... we can split it up in the form of (a+b)(a-b)

- UsukiDoll

a = x =u b = 2

- Bananas1234

i see

- Bananas1234

so what do i do next

- UsukiDoll

what do you have for the numerator first?

- Bananas1234

u + 2?

- UsukiDoll

no you're missing something
I'll give an example
(x^2-9) =(x+3)(x-3)
now follow that pattern with u^2-4

- UsukiDoll

it's 3 on the example because the square root of 9 is 3

- Bananas1234

i am not sure i am following you

- UsukiDoll

(u^2-4) the term u^2 is a perfect square and the same goes for 4 so the square root of u^2 is u and the square root of 4 is 2
whenever we have something like u^2 - 4 , it is a perfect square polynomial in the form of (u^2-4) = (u+2)(u-2)

- Bananas1234

ok

- UsukiDoll

now for the denominator
u^2 can also be written as uu... eventually you may be required to be swift in factoring and taking out like terms
u^2-2u I can take a u out and it becomes u(u-2)
to see it easier uu-2u and since we have a u on the left and u on the right we can take that out

- Bananas1234

ok

- UsukiDoll

so now we have (u+2)(u-2) / u(u-2) so what does the numerator and denoiminator have in common that we can remove.

- Bananas1234

u-2

- UsukiDoll

yes! so we have (u+2)/(u)

- Bananas1234

i think i understand better now

- UsukiDoll

hmm if we have to simplify further we can split (u+2)/(u) into 2 fractions because they have the same denominator
u/u +2/u
1+ 2/u or we can leave the answer like that

- Bananas1234

based on my options i think its ok to leave it

- UsukiDoll

yeah that's fine ^^

- Bananas1234

so is it u +2/u, u is not 0
or
u +2/u, u is not 2, u is not 0
? and how do i find out?

- Bananas1234

- UsukiDoll

the denominator of u is the whole entire thing
\[\frac{u+2}{u}\]

- UsukiDoll

since they share a single denominator we can split it up into 2 different fractions or leave it as is.

- UsukiDoll

\[\frac{u}{u} +\frac{2}{u} \rightarrow 1 + \frac{2}{u}\]

- UsukiDoll

we can't have u = 0 .. because anything divided by 0 is undefined.

- Bananas1234

i see

- Bananas1234

Thanks

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