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anonymous
 one year ago
please help. medal and fan
anonymous
 one year ago
please help. medal and fan

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volts (time t in seconds). The current through the circuit I(t) (in amperes) satisfies the differential equation: dI/dt + (R/L)I = (1/L)V(t) Find the solution to this equation with the initial condition I(0)=0, assuming that R=50Ω, L=5 H, and V(t) is constant with V(t)=10 V.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm having trouble differentiating it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I(e^(RT/L)) = integral: (V(t)e^(RT/L))/L

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0with the numbers plugged in Ie^(10t) = integral: (V(t)e^(10t))/5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's as far as I got

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe treat V(t) as a constant?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I also plugged in 10 for V(t) and got 1/5 for C when I(0)=0.

sparrow2
 one year ago
Best ResponseYou've already chosen the best response.0i(r/L) this is constant,isn't it?

sparrow2
 one year ago
Best ResponseYou've already chosen the best response.0because r/L is constant becasue r and L are constants

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ya when i plugged those values in I got e^10T

sparrow2
 one year ago
Best ResponseYou've already chosen the best response.0v(t) is also constant it's 10

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep, but the question is asking me to find an equation for V(t)

sparrow2
 one year ago
Best ResponseYou've already chosen the best response.0v(t)=10 this is equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wish it was, I already tried that lol

sparrow2
 one year ago
Best ResponseYou've already chosen the best response.0when it is writte above v(t)=10v v here is volt not a variable i guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think it is a constant but i'm not sure where i need to apply it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The only other part of the question is V(t) =

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0don't have the solution, my input: dl/dt = dl/dv*dv/dt for some reason I would be separating the variables and integrating when you integrate you add the constant here the constant is given as 10V

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433057995387:dw

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ di }{dt }+\frac{ r }{ l }i=\frac{ 1 }{ l}v(t)\\r=50\\l=5\\v(t)=10\\\frac{ di }{dt }+\frac{ 50 }{ 5 }i=\frac{ 1 }{ 5}10\\\] and now solve this differential equation \[\frac{ di }{dt }+10i=2\\ \rightarrow * e^{10t} \\e^{10t} (\frac{di}{dt}+10i)=2e^{10t}\\e^{10t} di +e^{10t} 10i dt =2e^{10t}dt\\now\\ \space \\\ d(e^{10t}i)=2e^{10t}dt \] now apply integral \[\int\limits_{0}^{t}d(e^{10t}i)=\int\limits_{0}^{t}2e^{10s}ds \\e^{10t}i(t)e^0i(0)=2e^{10t}2\] and now apply I(0)=0 so you have \[e^{10t}i(t)0=2(e^{10t}1)\\ \rightarrow * e^{10t} \\i(t)=2(1e^{10t})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@amoodarya I tried that but it was wrong. The question is asking for V(t) and i'm not sure what they want

amoodarya
 one year ago
Best ResponseYou've already chosen the best response.0v(t) is voltage of ? resistant or self ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yesh veryish goosh sir
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