Bananas1234
  • Bananas1234
Divide and simplify completely. Assume that no denominator equals zero. d^2-1/d^2-d divided by d - 1/d
Mathematics
katieb
  • katieb
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Bananas1234
  • Bananas1234
UnkleRhaukus
  • UnkleRhaukus
\[\frac{d^2-1}{d^2-d}\div\frac{d-1}d\\ =\frac{d^2-1}{d^2-d}\times\frac d{d-1}\\ =\]
UnkleRhaukus
  • UnkleRhaukus
factor the denominator of the first fraction . . .

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Bananas1234
  • Bananas1234
UnkleRhaukus
  • UnkleRhaukus
huh?
Bananas1234
  • Bananas1234
d^2 - 1/d^2
UnkleRhaukus
  • UnkleRhaukus
what is that susposed to be?
Bananas1234
  • Bananas1234
the answer
UnkleRhaukus
  • UnkleRhaukus
its not right
Bananas1234
  • Bananas1234
ok
UnkleRhaukus
  • UnkleRhaukus
factor the numerator and denominator of \(\dfrac{d^2-1}{d^2-d}\)
Bananas1234
  • Bananas1234
wouldn't the top be the same and the bottom be d^2?
Bananas1234
  • Bananas1234
UnkleRhaukus
  • UnkleRhaukus
nope
Bananas1234
  • Bananas1234
hmmm well then i am not sure :/ @UnkleRhaukus
UnkleRhaukus
  • UnkleRhaukus
can you factor d^2 - d ?
Bananas1234
  • Bananas1234
(d^2 -d) (d^2 + d)
UnkleRhaukus
  • UnkleRhaukus
d^2 - d = d*d - d = d(d-1)
Bananas1234
  • Bananas1234
oh
UnkleRhaukus
  • UnkleRhaukus
d^2-1 = (d-1)(d+1)
Bananas1234
  • Bananas1234
what do i do next?
Bananas1234
  • Bananas1234
UnkleRhaukus
  • UnkleRhaukus
\[\frac{d^2-1}{d^2-d}\div\frac{d-1}d\\ =\frac{d^2-1}{d^2-d}\times\frac d{d-1}\\ =\frac{(d-1)(d+1)}{d(d-1)}\times\frac{d}{d-1}\\ =\]
Bananas1234
  • Bananas1234
d + 1 / d - 1?
UnkleRhaukus
  • UnkleRhaukus
yep
Bananas1234
  • Bananas1234
Thank you

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