anonymous
  • anonymous
Can someone help me with 7th grade math
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
Can you make the screen shot a bit clearer? Which question are you working on?
anonymous
  • anonymous
yeah

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anonymous
  • anonymous
The one with jamie
anonymous
  • anonymous
Okay, i can help with this :)
anonymous
  • anonymous
bye
anonymous
  • anonymous
so, Were looking for the number of baseball cards. First, we have to know out of how many jamie pulled out, what fraction of that was baseball cards. We can find this by adding how many baseball cards and football cards jamie recorded. Using this, what do you think the fraction would be?
anonymous
  • anonymous
um would it be 6/60 *9/60?
anonymous
  • anonymous
Well, we need to find how many of the ones she/he pulled out were baseball cards, so it would be 6/15. Jamie pulled out 15 cards, and 6 of those are baseball cards. Does this make sense?
anonymous
  • anonymous
But werent there 60 cards how do we get 15?
anonymous
  • anonymous
\[\pi \]
anonymous
  • anonymous
Oh nevermind you added 6 and 9
anonymous
  • anonymous
Yes. so, now we have 6/15 because we only know how many baseball cards were in the amount jamie pulled out.
anonymous
  • anonymous
Yes
anonymous
  • anonymous
So, we need to figure out how many baseball cards are in the full stack. What times 15 equals 60? (Were basically doing the opposite of simplifying, were increasing it to make 15 have the same denominator as 60 :) )
anonymous
  • anonymous
\[\pi \]
anonymous
  • anonymous
4
anonymous
  • anonymous
Exactly! Great job! Now, what you do to the bottom you have to do to the top. So, 6 x 4 equals?
anonymous
  • anonymous
24
anonymous
  • anonymous
Yep! So, our new fraction is 24/60. So, in the 60 cards that jamie has, 24 are baseball cards! Great job @nerd_3.14 !!
anonymous
  • anonymous
So then whats the answer to the prroblem?
anonymous
  • anonymous
Nevermind im slow today got it thank you
anonymous
  • anonymous
No problem! Great job @nerd_3.14 !!

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