anonymous
  • anonymous
A 70.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45.0° with the mast. How much work did he do? A. 19,400 J B. 686 J C. 1,400 J D. 13,700 J :/
Physics
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anonymous
  • anonymous
A 70.0 kg sailor climbs a 28.3 m rope ladder at an angle of 45.0° with the mast. How much work did he do? A. 19,400 J B. 686 J C. 1,400 J D. 13,700 J :/
Physics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Michele_Laino
  • Michele_Laino
the requested work W is: \[W = mgd\cos \left( {45} \right) = 70 \times 9.81 \times 28.3 \times \cos 45\]
Michele_Laino
  • Michele_Laino
since we havfe to consider the projection of the weight force, along the direction of the displacement
Michele_Laino
  • Michele_Laino
have*

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anonymous
  • anonymous
ohh okay! and so we calculate and get 13741? so our solution is D? 13,700 J since it is approximation?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
yay!! thank you!!
Michele_Laino
  • Michele_Laino
ok! :)

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