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anonymous

  • one year ago

identify the oblique asymptote of f(x) = quantity x squared minus 4 x plus 8 over quantity x plus 2. y = 0 y = x - 2 y = x - 6 No oblique asymptote

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  1. anonymous
    • one year ago
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    \[f(x) = \frac{ x^2 - 4x + 8 }{ x + 2 }\]

  2. anonymous
    • one year ago
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    @paki @skullpatrol @nincompoop

  3. nincompoop
    • one year ago
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    what is an asymptote?

  4. anonymous
    • one year ago
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    idk i missed like a wee of school because i was sick and this is make up work and next week are exams

  5. nincompoop
    • one year ago
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    http://www.purplemath.com/modules/asymtote.htm

  6. anonymous
    • one year ago
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    so i basically factor?

  7. ybarrap
    • one year ago
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    You have an improper fraction because the degree of the numerator is 2 and the degree of the denominator is 1. When you divide a degree 2 by a degree 1 you end up with a degree 1 polynomial (at most). Doing synthetic division of this function you get |dw:1433095265662:dw| See - http://www.purplemath.com/modules/synthdiv.htm (for synthetic division process) It's always good to plot the function to visualize the asymptote: http://www.wolframalpha.com/input/?i=plot+%28x%5E2-4x%2B8%29%2F%28x%2B2%29+with+asymptote Does all this make sense?

  8. anonymous
    • one year ago
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    hey

  9. anonymous
    • one year ago
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    thanx @ybarrap

  10. ybarrap
    • one year ago
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    Hopefully you understood and the next one will be a easy!

  11. anonymous
    • one year ago
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    yeah i did thank you !

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