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anonymous

  • one year ago

Select the appropriate restrictions for the variables

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  1. anonymous
    • one year ago
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    |dw:1433093141289:dw|

  2. anonymous
    • one year ago
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    @Michele_Laino

  3. anonymous
    • one year ago
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    @Mehek14

  4. anonymous
    • one year ago
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    i will type the answer choices!

  5. Michele_Laino
    • one year ago
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    hint: we have to factor out the x at both numerator and denominator

  6. yadu123
    • one year ago
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    Since you cannot divide by 0 x cannot equal 0

  7. anonymous
    • one year ago
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    |dw:1433093348516:dw|

  8. yadu123
    • one year ago
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    you can cross out a

  9. anonymous
    • one year ago
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    |dw:1433093595414:dw|

  10. anonymous
    • one year ago
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    how do i do that ? @Michele_Laino

  11. anonymous
    • one year ago
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    are you there? @Michele_Laino

  12. Michele_Laino
    • one year ago
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    here are your steps: \[\frac{{5x - 3{x^2}}}{{2{x^4}}} = \frac{{x\left( {5 - 3x} \right)}}{{x\left( {2{x^3}} \right)}} = \frac{{5 - 3x}}{{2{x^3}}}\]

  13. anonymous
    • one year ago
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    which equals (x=0) @Michele_Laino

  14. anonymous
    • one year ago
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    so its c?

  15. Michele_Laino
    • one year ago
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    since you are dividing by x, then x can not be equal to zero

  16. anonymous
    • one year ago
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    oh ok!

  17. anonymous
    • one year ago
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    |dw:1433094463748:dw|

  18. anonymous
    • one year ago
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    @Michele_Laino

  19. Michele_Laino
    • one year ago
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    ok!

  20. anonymous
    • one year ago
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    im thinking its c?

  21. Michele_Laino
    • one year ago
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    that's right!

  22. anonymous
    • one year ago
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    i am going to post another question!

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