anonymous
  • anonymous
Select the appropriate restrictions for the variables
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1433093141289:dw|
anonymous
  • anonymous
@Michele_Laino
anonymous
  • anonymous
@Mehek14

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More answers

anonymous
  • anonymous
i will type the answer choices!
Michele_Laino
  • Michele_Laino
hint: we have to factor out the x at both numerator and denominator
yadu123
  • yadu123
Since you cannot divide by 0 x cannot equal 0
anonymous
  • anonymous
|dw:1433093348516:dw|
yadu123
  • yadu123
you can cross out a
anonymous
  • anonymous
|dw:1433093595414:dw|
anonymous
  • anonymous
how do i do that ? @Michele_Laino
anonymous
  • anonymous
are you there? @Michele_Laino
Michele_Laino
  • Michele_Laino
here are your steps: \[\frac{{5x - 3{x^2}}}{{2{x^4}}} = \frac{{x\left( {5 - 3x} \right)}}{{x\left( {2{x^3}} \right)}} = \frac{{5 - 3x}}{{2{x^3}}}\]
anonymous
  • anonymous
which equals (x=0) @Michele_Laino
anonymous
  • anonymous
so its c?
Michele_Laino
  • Michele_Laino
since you are dividing by x, then x can not be equal to zero
anonymous
  • anonymous
oh ok!
anonymous
  • anonymous
|dw:1433094463748:dw|
anonymous
  • anonymous
@Michele_Laino
Michele_Laino
  • Michele_Laino
ok!
anonymous
  • anonymous
im thinking its c?
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
i am going to post another question!

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