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well, whats our slope to start with?
the regression equation is: _______ the equation is already presented to you in slope intercept format. on the first line or 2
we are using test1 to predict test2 test1 is our independant variable, consider it an x and yes, thats the slope we want to interval about. what does this narrow our options to?
c and d
explain your reasoning for that ...
when we are developing a confidence interval for a given sample, we take the sample data as a basis for the interval, we center the interval around the samples data. spose a given sample has a mean of 3, and we want some interval to determine a range for the populations mean: 3 +- (something) defines the interval.
we are trying to determine a interval for a slope our data in this case, is centered about the slope of the regression line. slope +- (something) is our interval
l honestly have no idea...
what is the slope of our regression line?
the slope is 0.486
oh, so would it be a and b..?
since we are trying to determine a interval for a slope our data in this case, is centered about the slope of the regression line. slope +- (something) , is our interval ^^^^ right, A or B is going to be the most feasible options
now the question does not correspond to the solutions, in that 2.048 doesnt seem to be related to a 95% confidence interval, but we have to accept it nonetheless.
the standard error of the slope .... this part is formulaic. do you know the formula?
then you really cant proceed until you study up on it ... you know have a focus to study on. when you can determine the formula for me, we can proceed.
well, ive found some good news, we dont really need the formula since we have the output given to us
it appears that the standard error (standard deviation in some cases) of our test1 predictor is .... what does the output say?
thanks! for the link
yep, thats how i study and make sure im at least on the right track.
i wasnt sure if we needed to modify the deviation that was listed, or just use it. stat trek says to just use it
the 2.046 is better related to the z score of a 96% confidence interval 1.95 is the usual value for a 95% interval. so i dont know why they used the z value they did for this question but thats immaterial overall