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anonymous

  • one year ago

A sailboat moves north for a distance of 10.00 km when blown by a wind from the southeast with a force of 5.00 × 10^4 N. How much work was done by the wind? A. 0.00 J B. 3.54 * 10^5 J C. 3.54 * 10^8 J D. 5.00 * 10^8 J

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  1. Michele_Laino
    • one year ago
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    here is the situation described by your exercise: |dw:1433093509593:dw|

  2. anonymous
    • one year ago
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    yes:)

  3. Michele_Laino
    • one year ago
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    so the requested work is given by the subsequent formula: \[\begin{gathered} W = Fd\cos \l|dw:1433093749565:dw|eft( {45} \right) = 5 \times {10^4} \times {10^3} \times \cos 45 \hfill \\ \hfill \\ \end{gathered} \]

  4. anonymous
    • one year ago
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    the equation you wrote does not show on my side :(

  5. Michele_Laino
    • one year ago
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    oops... \[W = Fd\cos \left( {45} \right) = 5 \times {10^4} \times {10^3} \times \cos 45\]

  6. anonymous
    • one year ago
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    okay! so we get 35355339.06?

  7. anonymous
    • one year ago
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    so our solution is choice C?

  8. Michele_Laino
    • one year ago
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    yes! it is 3.54 * 10^8 joules (approximated value)

  9. anonymous
    • one year ago
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    yay!! :) so onto the next one!! :P

  10. Michele_Laino
    • one year ago
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    ok!

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