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anonymous
 one year ago
A culture started with 5,000 bacteria. After 4hours, it grew to 6,000 bacteria. Predict how many bacteria will be present after 17 hours.
Round your answer to the nearest whole number.
P=Ae^kt
PLEASE HELP, IDK HOW TO DO THIS
anonymous
 one year ago
A culture started with 5,000 bacteria. After 4hours, it grew to 6,000 bacteria. Predict how many bacteria will be present after 17 hours. Round your answer to the nearest whole number. P=Ae^kt PLEASE HELP, IDK HOW TO DO THIS

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, it is 1000 bact every four hours

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 17 hours isa odd number,

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk how to use this formula P=Ae^kt

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not 1000 every 4 hours. Just 1000 over the first 4 hours. In the formula, P is the amount at any time, A is the initial amount, k is a constant we have to find, and t is the time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Start with P = 5000e^(kt)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Plug in the given values for P and t and solve for k.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you please give me the answer i have 2 minutes left and i've never seen a problem like this before

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@boogaboo this is not a linear function where the rate is constant

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0when P = 5000 t =0 when P = 6000 t = 4 find P when t = 17

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you wanna do this the quick snappy way?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0grows by a factor of \(\frac{6000}{5000}=\frac{6}{5}\) every 4 hours model as \[\huge P(t)=5000\times( \frac{6}{5})^{\frac{t}{4}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if you want to know the population in 17 hours replace \(t\) by \(17\) and compute \[\huge P(17)=5000\times( \frac{6}{5})^{\frac{17}{4}}\]
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