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anonymous
 one year ago
Assume the readings on thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C. Find the probability that a randomly selected thermometer reads between 2.24 and 1.38.
The probability is =
anonymous
 one year ago
Assume the readings on thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C. Find the probability that a randomly selected thermometer reads between 2.24 and 1.38. The probability is =

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we are given a low value, a high value, a mean, and a deviation what function have we used that has these for inputs?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0By trying to find the area to the left of z?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1we have covered this before, its may be useful to make notes ....

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1how do we find the area between high and low values? the inverse of this operation defines a z score, we already have z scores so the invnorm function isnt going to be useful to us.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1thats the one and how do we input the information?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Annnd thats what I forgot :(

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1try to recall, what would you say is the most reasonable ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0normalcdf(1.38,2.24,0,1)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1good effort, 0,1 is in the right spots but low,high is off 2.24 is to the left of 1.38, since its less than 1.38

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1inputs are in order: low, high, mean, deviation

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1you can try it as high, low .. it might say you did an error tho :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the wolf takes the syntax: P((2.240)/1 <z< (1.380/1)), for a mean of 0 and sd of 1 just in case we need a reference to compare with

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so I tried Normalcdf(1.38,2.24,0,1) and it didn't work

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1now swap the high and low about Normalcdf(2.24,1.38,0,1) that should work out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ugh nope. Not that either... What am I doing wrong? Should it be Normalpdf?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1pdf isnt valid here. and i cant be sure that youve hit the buttons correctly :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1assuming you eventually get the hang of it, it shold give you a solution similar to this http://www.wolframalpha.com/input/?i=P%282.24%3Cz%3C1.38%29

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1CDF means: cumulative distribution function we are finding the sum of the area between 2 points, is a cumulative sum so we use the CDF function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would then be 0.07 for the probability? How can I get into Wolfram? (For free)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1PDF is a probability distribution function, and it relates to a single point ... ive never had a need to use the PDF function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Or 0.071 I can't figure out the rounding..

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1i use the wolf for free all the time ...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1what do you have to round to? what number of deies?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm for some reason it never lets me. Maybe I just don't know how to find what I am trying to input and look for I guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Four decimal places as needed

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the syntax can be daunting i agree. its taken me a few years to learn the little I have for it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok figured it out on my ti83 and I got .071247

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1then 2 or 3 decies is not appropriate .. 07120 < 07124 < 07130 4 6 we are closer to 0712

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I make that into a positive right?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1the negative is bad lol ... ignore that sign

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1most likely your high,low values are mixed around.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok lol! Thank you!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have plenty more that I still have that I am still confused about so you'll probably see me on here quite a bit

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1as long as you can recall what it is we need to use, and if im about, ill try to guide your efforts
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