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anonymous

  • one year ago

Assume the readings on thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C. Find the probability that a randomly selected thermometer reads between -2.24 and -1.38. The probability is =

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  1. amistre64
    • one year ago
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    and your thoughts?

  2. amistre64
    • one year ago
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    we are given a low value, a high value, a mean, and a deviation what function have we used that has these for inputs?

  3. anonymous
    • one year ago
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    By trying to find the area to the left of z?

  4. anonymous
    • one year ago
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    INVNORM?

  5. amistre64
    • one year ago
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    we have covered this before, its may be useful to make notes ....

  6. anonymous
    • one year ago
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    I agree ugh sorry

  7. amistre64
    • one year ago
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    how do we find the area between high and low values? the inverse of this operation defines a z score, we already have z scores so the invnorm function isnt going to be useful to us.

  8. anonymous
    • one year ago
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    normalcdf?

  9. amistre64
    • one year ago
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    thats the one and how do we input the information?

  10. anonymous
    • one year ago
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    Annnd thats what I forgot :(

  11. amistre64
    • one year ago
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    try to recall, what would you say is the most reasonable ?

  12. anonymous
    • one year ago
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    normalcdf(-1.38,-2.24,0,1)

  13. amistre64
    • one year ago
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    good effort, 0,1 is in the right spots but low,high is off -2.24 is to the left of -1.38, since its less than -1.38

  14. amistre64
    • one year ago
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    inputs are in order: low, high, mean, deviation

  15. amistre64
    • one year ago
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    you can try it as high, low .. it might say you did an error tho :)

  16. anonymous
    • one year ago
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    Ok, I'll try now

  17. amistre64
    • one year ago
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    the wolf takes the syntax: P((-2.24-0)/1 <z< (-1.38-0/1)), for a mean of 0 and sd of 1 just in case we need a reference to compare with

  18. anonymous
    • one year ago
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    Ok, so I tried Normalcdf(-1.38,-2.24,0,1) and it didn't work

  19. amistre64
    • one year ago
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    now swap the high and low about Normalcdf(-2.24,-1.38,0,1) that should work out

  20. anonymous
    • one year ago
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    Ugh nope. Not that either... What am I doing wrong? Should it be Normalpdf?

  21. amistre64
    • one year ago
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    pdf isnt valid here. and i cant be sure that youve hit the buttons correctly :)

  22. amistre64
    • one year ago
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    assuming you eventually get the hang of it, it shold give you a solution similar to this http://www.wolframalpha.com/input/?i=P%28-2.24%3Cz%3C-1.38%29

  23. amistre64
    • one year ago
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    CDF means: cumulative distribution function we are finding the sum of the area between 2 points, is a cumulative sum so we use the CDF function

  24. anonymous
    • one year ago
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    So it would then be 0.07 for the probability? How can I get into Wolfram? (For free)

  25. amistre64
    • one year ago
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    PDF is a probability distribution function, and it relates to a single point ... ive never had a need to use the PDF function

  26. anonymous
    • one year ago
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    Or 0.071 I can't figure out the rounding..

  27. amistre64
    • one year ago
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    i use the wolf for free all the time ...

  28. amistre64
    • one year ago
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    what do you have to round to? what number of deies?

  29. amistre64
    • one year ago
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    ** decies

  30. anonymous
    • one year ago
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    Hmmm for some reason it never lets me. Maybe I just don't know how to find what I am trying to input and look for I guess

  31. anonymous
    • one year ago
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    Four decimal places as needed

  32. amistre64
    • one year ago
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    the syntax can be daunting i agree. its taken me a few years to learn the little I have for it

  33. anonymous
    • one year ago
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    Ok figured it out on my ti83 and I got -.071247

  34. amistre64
    • one year ago
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    then 2 or 3 decies is not appropriate .. 07120 < 07124 < 07130 4 6 we are closer to 0712

  35. anonymous
    • one year ago
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    I make that into a positive right?

  36. amistre64
    • one year ago
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    the negative is bad lol ... ignore that sign

  37. amistre64
    • one year ago
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    most likely your high,low values are mixed around.

  38. anonymous
    • one year ago
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    Ok lol! Thank you!!!

  39. amistre64
    • one year ago
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    yep

  40. anonymous
    • one year ago
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    I have plenty more that I still have that I am still confused about so you'll probably see me on here quite a bit

  41. amistre64
    • one year ago
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    as long as you can recall what it is we need to use, and if im about, ill try to guide your efforts

  42. anonymous
    • one year ago
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    Thank you so much

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