anonymous
  • anonymous
Assume the readings on thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C. Find the probability that a randomly selected thermometer reads between -2.24 and -1.38. The probability is =
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

amistre64
  • amistre64
and your thoughts?
amistre64
  • amistre64
we are given a low value, a high value, a mean, and a deviation what function have we used that has these for inputs?
anonymous
  • anonymous
By trying to find the area to the left of z?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
INVNORM?
amistre64
  • amistre64
we have covered this before, its may be useful to make notes ....
anonymous
  • anonymous
I agree ugh sorry
amistre64
  • amistre64
how do we find the area between high and low values? the inverse of this operation defines a z score, we already have z scores so the invnorm function isnt going to be useful to us.
anonymous
  • anonymous
normalcdf?
amistre64
  • amistre64
thats the one and how do we input the information?
anonymous
  • anonymous
Annnd thats what I forgot :(
amistre64
  • amistre64
try to recall, what would you say is the most reasonable ?
anonymous
  • anonymous
normalcdf(-1.38,-2.24,0,1)
amistre64
  • amistre64
good effort, 0,1 is in the right spots but low,high is off -2.24 is to the left of -1.38, since its less than -1.38
amistre64
  • amistre64
inputs are in order: low, high, mean, deviation
amistre64
  • amistre64
you can try it as high, low .. it might say you did an error tho :)
anonymous
  • anonymous
Ok, I'll try now
amistre64
  • amistre64
the wolf takes the syntax: P((-2.24-0)/1
anonymous
  • anonymous
Ok, so I tried Normalcdf(-1.38,-2.24,0,1) and it didn't work
amistre64
  • amistre64
now swap the high and low about Normalcdf(-2.24,-1.38,0,1) that should work out
anonymous
  • anonymous
Ugh nope. Not that either... What am I doing wrong? Should it be Normalpdf?
amistre64
  • amistre64
pdf isnt valid here. and i cant be sure that youve hit the buttons correctly :)
amistre64
  • amistre64
assuming you eventually get the hang of it, it shold give you a solution similar to this http://www.wolframalpha.com/input/?i=P%28-2.24%3Cz%3C-1.38%29
amistre64
  • amistre64
CDF means: cumulative distribution function we are finding the sum of the area between 2 points, is a cumulative sum so we use the CDF function
anonymous
  • anonymous
So it would then be 0.07 for the probability? How can I get into Wolfram? (For free)
amistre64
  • amistre64
PDF is a probability distribution function, and it relates to a single point ... ive never had a need to use the PDF function
anonymous
  • anonymous
Or 0.071 I can't figure out the rounding..
amistre64
  • amistre64
i use the wolf for free all the time ...
amistre64
  • amistre64
what do you have to round to? what number of deies?
amistre64
  • amistre64
** decies
anonymous
  • anonymous
Hmmm for some reason it never lets me. Maybe I just don't know how to find what I am trying to input and look for I guess
anonymous
  • anonymous
Four decimal places as needed
amistre64
  • amistre64
the syntax can be daunting i agree. its taken me a few years to learn the little I have for it
anonymous
  • anonymous
Ok figured it out on my ti83 and I got -.071247
amistre64
  • amistre64
then 2 or 3 decies is not appropriate .. 07120 < 07124 < 07130 4 6 we are closer to 0712
anonymous
  • anonymous
I make that into a positive right?
amistre64
  • amistre64
the negative is bad lol ... ignore that sign
amistre64
  • amistre64
most likely your high,low values are mixed around.
anonymous
  • anonymous
Ok lol! Thank you!!!
amistre64
  • amistre64
yep
anonymous
  • anonymous
I have plenty more that I still have that I am still confused about so you'll probably see me on here quite a bit
amistre64
  • amistre64
as long as you can recall what it is we need to use, and if im about, ill try to guide your efforts
anonymous
  • anonymous
Thank you so much

Looking for something else?

Not the answer you are looking for? Search for more explanations.