anonymous
  • anonymous
Simplify and select the answer with the appropriate restrictions for the variables
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1433096866824:dw|
mathstudent55
  • mathstudent55
Factor the numerator and denominator.
anonymous
  • anonymous

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anonymous
  • anonymous
|dw:1433096969256:dw|
anonymous
  • anonymous
anonymous
  • anonymous
what do you think? @Michele_Laino
Michele_Laino
  • Michele_Laino
please, solve the subsequent quadratic equation, first: \[{x^2} - 2x - 8 = 0\]
anonymous
  • anonymous
how do you do that? @Michele_Laino
welshfella
  • welshfella
this will factor to the form (x + a)(x + b) where ab = -8 and a + b = -2 can you find what a and b will be?
anonymous
  • anonymous
8 and 2? since, (8+-8)(2+-2)=0
Michele_Laino
  • Michele_Laino
alternatively, you can apply the standard formula, so you have to compute this: \[x = \frac{{2 \pm \sqrt {{2^2} - 4 \times 1 \times \left( { - 8} \right)} }}{2}\]
welshfella
  • welshfella
no that won't fit factoring -8 will help:- -8 = -4 * 2 or -8 = 4 * -2 which ons will give you -2 when added?
anonymous
  • anonymous
-2 and 1?
anonymous
  • anonymous
Michele_Laino
  • Michele_Laino
I got: 4, and -2
anonymous
  • anonymous
oh ok
Michele_Laino
  • Michele_Laino
so we can write this factorization: \[{x^2} - 2x - 8 = \left( {x - 4} \right)\left( {x + 2} \right)\]
anonymous
  • anonymous
i got d?
Michele_Laino
  • Michele_Laino
substituting into your expression, we get: \[\frac{{3{x^2} + 6x}}{{{x^2} - 2x - 8}} = \frac{{3x\left( {x + 2} \right)}}{{\left( {x - 4} \right)\left( {x + 2} \right)}}\]
anonymous
  • anonymous
nvm bc it has to match up to -4 and 2
Michele_Laino
  • Michele_Laino
that's right, it is option D
anonymous
  • anonymous
wait so is it -4 and 2 or 4 and -2
welshfella
  • welshfella
-4 and 2 - in order to get the -2x
anonymous
  • anonymous
i will tag you in my next question!!:D
mathstudent55
  • mathstudent55
|dw:1433100747460:dw|

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