anonymous
  • anonymous
Simplify sin^3(x)sec^2(x)-sin^2(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Nnesha
  • Nnesha
take out common factor
anonymous
  • anonymous
there isn't one.
Nnesha
  • Nnesha
yes there is let's say sin = x and sec = y so x^3 y - x^2 what is common factor ?

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More answers

anonymous
  • anonymous
sin^2
Nnesha
  • Nnesha
yep right sin^2( ) what should be in the parentheses ?? :-)
anonymous
  • anonymous
\[\sin^2x(sinxsec^2x-1)\]
anonymous
  • anonymous
I need to simplify it more. How would I do that?
Nnesha
  • Nnesha
gimme a sec :3 i'm working on it
anonymous
  • anonymous
ok. :) I've tried a lot of different ways myself and it never gets real simple.
freckles
  • freckles
doesn't really seem like you can simplify it
Nnesha
  • Nnesha
i guess try this identity 1+tan^2 =sec^2 otherwise that's it sin^2(sin(x)sec^2-1)
freckles
  • freckles
for some reason I read sin^2(x)sec^2(x)-sin^2(x) at first sin^2(x)(sec^2(x)-1) sec^2(x)tan^2(x)
freckles
  • freckles
but we had sin^3(x)sec^2(x)-sin^2(x)
Nnesha
  • Nnesha
ye
freckles
  • freckles
maybe we are just suppose to rewrite it (not really simplify) are there are choices @AEB047 ?
anonymous
  • anonymous
no choices.
Nnesha
  • Nnesha
or you can write sin^3 as sin^2 times sin
freckles
  • freckles
earlier you said you needed to simplify more how did you know that like is this something you are trying to simplify to exactly?
Nnesha
  • Nnesha
\[ \sin^3(x)\sec^2(x)-\sin^2(x)\] write sec^2 = 1/cos^2 \[\sin(x) \times \sin^2(x) \times \frac{ 1 }{ \cos^2(x) } - \sin^2(x)\] sin^2/cos^2 = tan^2
anonymous
  • anonymous
ok, so we can end up with: \[\frac{ \sin^3x }{ \cos^2x }-\sin^2x\] or \[\sin^2x(\frac{ sinx }{ \cos^2x }-1)\] or \[\tan^2xsinx-\sin^2x\] Which one is the most simplified, do you think?
freckles
  • freckles
it doesn't matter they are both ugly :p
Nnesha
  • Nnesha
i'll go with de last one :P i hate fraction >.<
anonymous
  • anonymous
same. ok. thanks!
Nnesha
  • Nnesha
np :-)
freckles
  • freckles
@AEB047 can I ask where you got this question from: Simplify sin^3(x)sec^2(x)-sin^2(x)
freckles
  • freckles
Like did your teacher come up with it? Was that the original problem?
freckles
  • freckles
I'm just not convinced the "original problem" is actually the original problem Because to me no simpler form has been given to the "original" unless your teacher has clearly defined the word "simplify"

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