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anonymous
 one year ago
Simplify sin^3(x)sec^2(x)sin^2(x)
anonymous
 one year ago
Simplify sin^3(x)sec^2(x)sin^2(x)

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yes there is let's say sin = x and sec = y so x^3 y  x^2 what is common factor ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yep right sin^2( ) what should be in the parentheses ?? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\sin^2x(sinxsec^2x1)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need to simplify it more. How would I do that?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3gimme a sec :3 i'm working on it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. :) I've tried a lot of different ways myself and it never gets real simple.

freckles
 one year ago
Best ResponseYou've already chosen the best response.1doesn't really seem like you can simplify it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3i guess try this identity 1+tan^2 =sec^2 otherwise that's it sin^2(sin(x)sec^21)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1for some reason I read sin^2(x)sec^2(x)sin^2(x) at first sin^2(x)(sec^2(x)1) sec^2(x)tan^2(x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1but we had sin^3(x)sec^2(x)sin^2(x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1maybe we are just suppose to rewrite it (not really simplify) are there are choices @AEB047 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3or you can write sin^3 as sin^2 times sin

freckles
 one year ago
Best ResponseYou've already chosen the best response.1earlier you said you needed to simplify more how did you know that like is this something you are trying to simplify to exactly?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[ \sin^3(x)\sec^2(x)\sin^2(x)\] write sec^2 = 1/cos^2 \[\sin(x) \times \sin^2(x) \times \frac{ 1 }{ \cos^2(x) }  \sin^2(x)\] sin^2/cos^2 = tan^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so we can end up with: \[\frac{ \sin^3x }{ \cos^2x }\sin^2x\] or \[\sin^2x(\frac{ sinx }{ \cos^2x }1)\] or \[\tan^2xsinx\sin^2x\] Which one is the most simplified, do you think?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1it doesn't matter they are both ugly :p

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3i'll go with de last one :P i hate fraction >.<

freckles
 one year ago
Best ResponseYou've already chosen the best response.1@AEB047 can I ask where you got this question from: Simplify sin^3(x)sec^2(x)sin^2(x)

freckles
 one year ago
Best ResponseYou've already chosen the best response.1Like did your teacher come up with it? Was that the original problem?

freckles
 one year ago
Best ResponseYou've already chosen the best response.1I'm just not convinced the "original problem" is actually the original problem Because to me no simpler form has been given to the "original" unless your teacher has clearly defined the word "simplify"
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