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anonymous

  • one year ago

Simplify sin^3(x)sec^2(x)-sin^2(x)

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  1. Nnesha
    • one year ago
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    take out common factor

  2. anonymous
    • one year ago
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    there isn't one.

  3. Nnesha
    • one year ago
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    yes there is let's say sin = x and sec = y so x^3 y - x^2 what is common factor ?

  4. anonymous
    • one year ago
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    sin^2

  5. Nnesha
    • one year ago
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    yep right sin^2( ) what should be in the parentheses ?? :-)

  6. anonymous
    • one year ago
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    \[\sin^2x(sinxsec^2x-1)\]

  7. anonymous
    • one year ago
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    I need to simplify it more. How would I do that?

  8. Nnesha
    • one year ago
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    gimme a sec :3 i'm working on it

  9. anonymous
    • one year ago
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    ok. :) I've tried a lot of different ways myself and it never gets real simple.

  10. freckles
    • one year ago
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    doesn't really seem like you can simplify it

  11. Nnesha
    • one year ago
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    i guess try this identity 1+tan^2 =sec^2 otherwise that's it sin^2(sin(x)sec^2-1)

  12. freckles
    • one year ago
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    for some reason I read sin^2(x)sec^2(x)-sin^2(x) at first sin^2(x)(sec^2(x)-1) sec^2(x)tan^2(x)

  13. freckles
    • one year ago
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    but we had sin^3(x)sec^2(x)-sin^2(x)

  14. Nnesha
    • one year ago
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    ye

  15. freckles
    • one year ago
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    maybe we are just suppose to rewrite it (not really simplify) are there are choices @AEB047 ?

  16. anonymous
    • one year ago
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    no choices.

  17. Nnesha
    • one year ago
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    or you can write sin^3 as sin^2 times sin

  18. freckles
    • one year ago
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    earlier you said you needed to simplify more how did you know that like is this something you are trying to simplify to exactly?

  19. Nnesha
    • one year ago
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    \[ \sin^3(x)\sec^2(x)-\sin^2(x)\] write sec^2 = 1/cos^2 \[\sin(x) \times \sin^2(x) \times \frac{ 1 }{ \cos^2(x) } - \sin^2(x)\] sin^2/cos^2 = tan^2

  20. anonymous
    • one year ago
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    ok, so we can end up with: \[\frac{ \sin^3x }{ \cos^2x }-\sin^2x\] or \[\sin^2x(\frac{ sinx }{ \cos^2x }-1)\] or \[\tan^2xsinx-\sin^2x\] Which one is the most simplified, do you think?

  21. freckles
    • one year ago
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    it doesn't matter they are both ugly :p

  22. Nnesha
    • one year ago
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    i'll go with de last one :P i hate fraction >.<

  23. anonymous
    • one year ago
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    same. ok. thanks!

  24. Nnesha
    • one year ago
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    np :-)

  25. freckles
    • one year ago
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    @AEB047 can I ask where you got this question from: Simplify sin^3(x)sec^2(x)-sin^2(x)

  26. freckles
    • one year ago
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    Like did your teacher come up with it? Was that the original problem?

  27. freckles
    • one year ago
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    I'm just not convinced the "original problem" is actually the original problem Because to me no simpler form has been given to the "original" unless your teacher has clearly defined the word "simplify"

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