Part A: What does the x-intercept of the function for car 1 represent? (2 points) Part B: What does the y-intercept of the function for car 2 represent? (2 points) Part C: What is the domain of the functions for car 1 and car 2? (2 points) Part D: What is the average rate of change from x = 20 to x = 30 for the function representing the motion for car 2? What does the value of this average rate of change represent? (4 points)

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Part A: What does the x-intercept of the function for car 1 represent? (2 points) Part B: What does the y-intercept of the function for car 2 represent? (2 points) Part C: What is the domain of the functions for car 1 and car 2? (2 points) Part D: What is the average rate of change from x = 20 to x = 30 for the function representing the motion for car 2? What does the value of this average rate of change represent? (4 points)

Mathematics
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1 Attachment
A x-intercept is the time 60 minutes he has taken to travel to his destination.

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B This represents the distance (60 km) away form the cars destination
C The domain is the values of the times ( what do you think the values are?)
D:- Hint at time = 20 car 2 is 40 miles for its destination at time = 30 it is 34 miles form its destination
@welshfella I dont understand C nor D. could you please explain more?
hi welsh
So about c i dont understand what domain (x) values they want
The domain is the possible values of the horizontal (time) axis. From the diagram what do you think they are? Note that you have to consider both Car A and Car B together.
[0,positive infinitey)
?
oopps sorry I think they want a domain for Car A and another for Car B.
Oh okay
Thats the correct domain for car B what about Car A?
could you give me the domain for car b and i figure it out for car a?
I got it so for A the domain would be [0,60)
Right?
[0 , +INF) is domain for car B
yes thats right for A
Yes as i said earlier so the domain for car A is [0,60)
no 60 is INCLUDED in the Domain so it is [0,60]
square bracket after the 60
okay cool so for part C Part C: The domain for Car A would be [0,60) and for Car B the domain is [0,+INF)
Oh sorry i mean [0,60]
yes thats right
And you provided me with the answers for a and b right?
yes
So all i need is D please explain it cause i dont understand it what so ever
the average rate of change = average speed of Car 2 during the period 20 to 30 minutes
Okay
and this is (40-34) / (30-20) kms / minute
@welshfella Could you provide me with the answer im hopeless
what is 40 - 34 ? and 30 - 20 ? i'm sure you can do that
40-34= 6 and 30-20 = 10
what do i do with theese numbers?
right so speed = 6 / 10 = 0.6 kms/minute
Okay
sorry i didnt provide you with this char Time (in minutes) x 0 10 20 30 40 50 60 Car 1 (in km) y 60 50 40 30 20 10 0 Car 2 (in km) y 60 49.02438 40.05648 32.72904 26.742 21.8502 17.85318
Time (in minutes) x 0 10 20 30 40 50 60 Car 1 (in km) y 60 50 40 30 20 10 0 Car 2 (in km) y 60 49.02438 40.05648 32.72904 26.742 21.8502 17.85318
this value represents the car's average speed between times 20 and 30 minutes
I hope this chart does not change our answers
So my answer for Part D would be Part D: The average rate of change is speed = 6 / 10 = 0.6 kms/minute, and this represents the car's average speed between times 20 and 30 minutes
@welshfella Is that right
?
the speed of car B will be different as i just read the values off the graph
Oh okay so my second part of the answer is right but now i need to figure out the speed using the chart?
speed = (40.05648 - 32.72904) / 10
ok so its .732744
So .732744 my average rate of change??
kms / minute Yes
yes
Okay so my Anser for part D is
The average rate of change is 0.732744 kms/minutes and this represents the car's average speed between times 20 and 30 minutes.
Is that correct?
yes
Thanks for your help

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