anonymous
  • anonymous
a worker uses a block and tackle with a mechanical advantage of 1.74 to lift a 225 N crate a distance of 16.5 m. He pulls 33.0 m of rope. What force did she use to lift the crate? 29.0 N , 129 N , 57.0 N , or 392 N
Physics
katieb
  • katieb
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Michele_Laino
  • Michele_Laino
please, wait a moment a student asked me for help in Mathematics
anonymous
  • anonymous
ok!
Michele_Laino
  • Michele_Laino
here we have to consider the work done by the weight force of the crate, which is: \[{W_1} = Fs = 225 \times 16.5 = ...\]

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Michele_Laino
  • Michele_Laino
what do you get?
anonymous
  • anonymous
i get 3712.5
anonymous
  • anonymous
is that right?
Michele_Laino
  • Michele_Laino
ok! that's right!
anonymous
  • anonymous
what happens next? to find the solution to the problem?
Michele_Laino
  • Michele_Laino
next we have to consider the work W_2 done by the worker, which is: \[{W_2} = Rd\] Now we don't know what is R
Michele_Laino
  • Michele_Laino
whereas d=330 meters
Michele_Laino
  • Michele_Laino
oops..d=33 meters
anonymous
  • anonymous
ok!
Michele_Laino
  • Michele_Laino
in order to find the value of the requasted force R, we have to apply this condition: \[\Large 1.74 = \frac{{3712.5}}{{33R}}\] so what is R?
anonymous
  • anonymous
64.655?
Michele_Laino
  • Michele_Laino
sorry, it is the wrong result, please wait, I revise my reasoning
anonymous
  • anonymous
ok!
Michele_Laino
  • Michele_Laino
the requested force is given by the subsequent simple computation: \[1.74 = \frac{R}{F},\quad R = 1.74F = 1.74 \times 225 = ...Newtons\] here I have applied the definition, of advantage of a simple machine, namely: \[{\text{advantage}} = \frac{{{\text{resistive force}}}}{{{\text{agent force}}}}\]
anonymous
  • anonymous
391.5? so our solution is 392 N?
Michele_Laino
  • Michele_Laino
yes! that's right!
anonymous
  • anonymous
yay!
Michele_Laino
  • Michele_Laino
:)

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