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Oh well maybe I needed to make that decimal into a percentage...

98.6% oops

but what does the information mean? i cant make sense of what it is asking of us

does it mean that we want to find an 98.6% interval?

that one reads better

Sorry :/

2nd vars

or stats?

2nd vars is a button combination, which takes us to a distribution menu.

press it and see what we get for function options ...

id say the 3rd for invnorm

So Id then put in my new percentage and input (0.1) and (0.2)

work it 2 times ... use .01 and .02

.10 is 10%; .01 is 1%

So invnorm(98.6, .01,.02)

or (98.6,1,2)

no, its exactly like a wrote above
invnorm(.01)

-2.326

and invnorm(.02) is?

-2.053

Would I then take out the negative? Also, would I make them a percentage or leave as a decimal?

Ok, leave as decimal. I just read that

So the top should be rounded to 2.33?

for the 1%

no, i mentioned nothing about rounding.

Oh ok so leave as is

what is: 63.5 -2.326(2.5)
and what is: 63.5 +2.053(2.5)

2.326 and 2.053

those are z values, we use them to define the interval with ..

invnormcdf?

normalcdf***

-.9999 for the first

when you get around to answering my question, let me know ...

and -1.4321 for the second

I know. I was using the normalcdf. I thought that is what I needed to use..

no, we simply need to use this
63.5 -2.326(2.5)

57.685

for the first

68.6325 for the second

Sorry about the confusion

Thank you again for your help. I really do appreciate it.

your welcome