anonymous one year ago Identify the vertical asymptotes of f(x) = 10 over quantity x squared minus 7x minus 30. x = 10 and x = 3 x = 10 and x = -3 x = -10 and x = 3 x = -10 and x = -3

1. anonymous

$f(x) = \frac{ 10 }{ x^2 -7x -30 }$

2. misty1212

set $x^2-7x-30=0$ solve for $$x$$

3. anonymous

okay give me a sec

4. anonymous

fortunalely for you this factors as $(x-10)(x+3)=0$ so the zeros are easy to find

5. misty1212

yeah @satellite73 gave you a huge hint there

6. anonymous

so its x = -10 and x = 3

7. misty1212

no dear

8. misty1212

$x-10=0\\ x=10$

9. misty1212

also $x+3=0\\ x=-3$

10. anonymous

oh so i have to bring it to the other side okay i see

11. misty1212

riiiiiigght

12. anonymous

thnx i have one more do you mind helping with?

13. misty1212

sure

14. anonymous

Identify the horizontal asymptote of f(x) = quantity 2 x minus 1 over quantity x squared minus 7 x plus 3. y = 0 y = 1 over 2 y = 2 No horizontal asymptote

15. anonymous

$f(x) = \frac{ 2x - 1 }{ x^2 - 7x +3 }$

16. anonymous

do i basically do the same thing as before?

17. misty1212

no!!

18. misty1212

horizontal not vertical

19. anonymous

oh so what do i need to do?

20. misty1212

the degree of the numerator is less than the degree of the denominator

21. misty1212

the degree of the numerator is 1, the degree of the denominator i s2

22. misty1212

that means the denominator grows faster than the numerator so the horizontal asymptote is $y=0$

23. anonymous

thank you so much!!!

24. anonymous

i gtg but i have lie 5 more questions to do later can you help with?

25. misty1212

sure dear if i am on