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anonymous

  • one year ago

A man uses a lever jack to lift a 2.00 * 10^3 kg car to change a tire. Each stroke of the jack lift the car a distance of 5.00 * 10^-3 m. The vertical displacement of the handle is 0.75 m for each stroke. How much total force does he use with each stroke of the jack? A. 3.0 * 10^5 N B. 2.9 * 10^6 N C. 131 N D. 19, 600 N

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  1. Michele_Laino
    • one year ago
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    here we have to apply the virtual work principle, namely the motor work has to be equal to the resistive work. So we can write: \[F \cdot 5 \times {10^{ - 3}} = 2 \times {10^3} \times 0.75\] what is F?

  2. Michele_Laino
    • one year ago
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    oops.. I have made a typo, here is the right formula: \[\Large F \cdot 5 \times {10^{ - 3}} = 2 \times {10^3} \times 9.81 \times 0.75\]

  3. Michele_Laino
    • one year ago
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    since we know the mass of our car, which is 2,000 Kg

  4. anonymous
    • one year ago
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    2943000 ? so our solution is choice B?

  5. Michele_Laino
    • one year ago
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    yes! That's right!

  6. anonymous
    • one year ago
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    yay!! thank you!! :D

  7. Michele_Laino
    • one year ago
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    :)

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