anonymous
  • anonymous
A man uses a lever jack to lift a 2.00 * 10^3 kg car to change a tire. Each stroke of the jack lift the car a distance of 5.00 * 10^-3 m. The vertical displacement of the handle is 0.75 m for each stroke. How much total force does he use with each stroke of the jack? A. 3.0 * 10^5 N B. 2.9 * 10^6 N C. 131 N D. 19, 600 N
Physics
chestercat
  • chestercat
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Michele_Laino
  • Michele_Laino
here we have to apply the virtual work principle, namely the motor work has to be equal to the resistive work. So we can write: \[F \cdot 5 \times {10^{ - 3}} = 2 \times {10^3} \times 0.75\] what is F?
Michele_Laino
  • Michele_Laino
oops.. I have made a typo, here is the right formula: \[\Large F \cdot 5 \times {10^{ - 3}} = 2 \times {10^3} \times 9.81 \times 0.75\]
Michele_Laino
  • Michele_Laino
since we know the mass of our car, which is 2,000 Kg

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anonymous
  • anonymous
2943000 ? so our solution is choice B?
Michele_Laino
  • Michele_Laino
yes! That's right!
anonymous
  • anonymous
yay!! thank you!! :D
Michele_Laino
  • Michele_Laino
:)

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