anonymous
  • anonymous
Hey guys, I really need help! Will fan and medal :) Scores on a statewide standardized test are normally distributed with a mean of 12.89 and a standard deviation of 1.95. Certificates are given to students whose scores are in the top 2% of those who took the test. This means that they scored better than 98% of the other test takers. Marcus received his score of 13.7 on the exam and is wondering why he didn’t receive a certificate. Show all work to determine whether Marcus’ score was high enough to earn a certificate. Write Marcus a letter about why he didn't recieve a certificate.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Oh, and include a brief summary of your statistical analysis in your letter. :) Almost forgot.
Vocaloid
  • Vocaloid
his score is 13.7, the mean is 12.89, and the standard deviation is 1.95 convert his score to a z-score using the formula z-score = (given value - mean)/standard deviation then, use your calculator to determine the percentage of data values that fall below mark's score (normalcdf(-99, marks score)). if this value is greater than 0.98, then that means that Mark is in the top 2%. Otherwise, Mark is not in the top 2%.
Vocaloid
  • Vocaloid
small correction: normalcdf(-99, marks z-score)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So the z-score would be 13.7 - 12.89/1.95?
Vocaloid
  • Vocaloid
parentheses
anonymous
  • anonymous
So (13.7 - 12.89)/1.95?
Vocaloid
  • Vocaloid
yes
anonymous
  • anonymous
Now, I'm kind of confused about finding the marks below Marcus' score...
Vocaloid
  • Vocaloid
normalcdf(-99, marcus' z-score) I meant to say "Marcus", not "Mark")
anonymous
  • anonymous
Sorry, the data points below Marcus' score
Vocaloid
  • Vocaloid
what is normalcdf(-99, marcus' z-score)?
anonymous
  • anonymous
What does normalcdf mean?
Vocaloid
  • Vocaloid
do you know how to use a graphing calculator?
anonymous
  • anonymous
Umm, no... But I have a regular scientific one
anonymous
  • anonymous
I don't need one for what I'm doing... Maybe... I'm not sure lol :P
Vocaloid
  • Vocaloid
hm, did your teacher show you how to use a z-table?
1 Attachment
anonymous
  • anonymous
Yes :) I have a z-table for positive and negative values.
Vocaloid
  • Vocaloid
great! Marcus' z-score is 0.415, do you know how to use the z-table to find the area to the left of the z-score?
anonymous
  • anonymous
I think so. Is it .65910?
Vocaloid
  • Vocaloid
yup, that's about what I got, too! do you know what .65910 means?
Vocaloid
  • Vocaloid
I mean, do you understand what that number represents?
anonymous
  • anonymous
It means that he falls in with the scores of %65.9 of his class?
Vocaloid
  • Vocaloid
not quite, it means that he scored better than 65.9% of the other students in order for Marcus to be in the top 2% and get the certificate, he needs to score better than 98% of all the other students so, do you think he got the certificate?
anonymous
  • anonymous
Ooh, ok! :) Nope, he didn't.
Vocaloid
  • Vocaloid
great, we've answered the question! good job
anonymous
  • anonymous
Yay! Thank you so much @Vocaloid
anonymous
  • anonymous
I fanned and medaled :)
Vocaloid
  • Vocaloid
thanks, I really appreciate it ^ ^
anonymous
  • anonymous
Np :) ttyl!

Looking for something else?

Not the answer you are looking for? Search for more explanations.