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Oh, and include a brief summary of your statistical analysis in your letter. :) Almost forgot.
his score is 13.7, the mean is 12.89, and the standard deviation is 1.95 convert his score to a z-score using the formula z-score = (given value - mean)/standard deviation then, use your calculator to determine the percentage of data values that fall below mark's score (normalcdf(-99, marks score)). if this value is greater than 0.98, then that means that Mark is in the top 2%. Otherwise, Mark is not in the top 2%.
small correction: normalcdf(-99, marks z-score)
So the z-score would be 13.7 - 12.89/1.95?
So (13.7 - 12.89)/1.95?
Now, I'm kind of confused about finding the marks below Marcus' score...
normalcdf(-99, marcus' z-score) I meant to say "Marcus", not "Mark")
Sorry, the data points below Marcus' score
what is normalcdf(-99, marcus' z-score)?
What does normalcdf mean?
do you know how to use a graphing calculator?
Umm, no... But I have a regular scientific one
I don't need one for what I'm doing... Maybe... I'm not sure lol :P
Yes :) I have a z-table for positive and negative values.
great! Marcus' z-score is 0.415, do you know how to use the z-table to find the area to the left of the z-score?
I think so. Is it .65910?
yup, that's about what I got, too! do you know what .65910 means?
I mean, do you understand what that number represents?
It means that he falls in with the scores of %65.9 of his class?
not quite, it means that he scored better than 65.9% of the other students in order for Marcus to be in the top 2% and get the certificate, he needs to score better than 98% of all the other students so, do you think he got the certificate?
Ooh, ok! :) Nope, he didn't.
great, we've answered the question! good job
Yay! Thank you so much @Vocaloid
I fanned and medaled :)
thanks, I really appreciate it ^ ^
Np :) ttyl!