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anonymous

  • one year ago

which is the standard form of the equation with p=18, phi =5pi/4?

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  1. skullpatrol
    • one year ago
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    check the question please

  2. Haseeb96
    • one year ago
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    Is this question complete ?

  3. anonymous
    • one year ago
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    this question is complete.. its trig identities.. so we're going off of the equation x cos phi + y sin phi - p=0

  4. Ali0094
    • one year ago
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    what does PHI mean?!!

  5. skullpatrol
    • one year ago
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    how was the question complete when you did not give the equation?

  6. anonymous
    • one year ago
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    phi looks like this... \[\phi \]

  7. anonymous
    • one year ago
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    because you are just suppose to know it... this was the question lol

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  8. skullpatrol
    • one year ago
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    |dw:1433104243974:dw|

  9. Ali0094
    • one year ago
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    what a hard question...lol

  10. anonymous
    • one year ago
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    thats correct @skullpatrol .. and then what i did next was convert the radian 5pi/4 into degrees to make it easier to simplify

  11. skullpatrol
    • one year ago
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    good, what did you get?

  12. anonymous
    • one year ago
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    i got 225 degrees.. which simplifys each cos and sin to -sqrt2/2 i believe

  13. skullpatrol
    • one year ago
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    ok, substitute the value into the equation please :)

  14. anonymous
    • one year ago
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    |dw:1433104713424:dw| and then we'd times the whole thing by -2 to further simplify....correct...?

  15. skullpatrol
    • one year ago
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    |dw:1433104740209:dw|

  16. skullpatrol
    • one year ago
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    what happened to the variable "y"?

  17. anonymous
    • one year ago
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    oh sorry i forgot it... lol

  18. anonymous
    • one year ago
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    anyway.. id get the final equation \[\sqrt{2}x+\sqrt{2}y+36 \] right?

  19. skullpatrol
    • one year ago
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    that^ is not an equation, it is an expression

  20. anonymous
    • one year ago
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    =0 on the end

  21. skullpatrol
    • one year ago
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    an equation has an equals sign, right?

  22. anonymous
    • one year ago
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    hahaha so ive been told..

  23. skullpatrol
    • one year ago
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    and the signs are not right :(

  24. anonymous
    • one year ago
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    wait really? whys that

  25. skullpatrol
    • one year ago
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    |dw:1433105082303:dw|

  26. anonymous
    • one year ago
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    |dw:1433105127782:dw| this is what i did

  27. skullpatrol
    • one year ago
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    |dw:1433105213074:dw|

  28. anonymous
    • one year ago
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    okay... besides from correcting ever single minor thing.. i believe i did this problem correct. thanks for your time

  29. skullpatrol
    • one year ago
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    You're answer is right :)

  30. skullpatrol
    • one year ago
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    thanks for trying to learn

  31. skullpatrol
    • one year ago
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    I apologize for "correcting every single minor thing..."

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