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anonymous
 one year ago
If 5x^2 + y^4 = −9 then evaluate d^2y/dx^2 when x = 2 and y = 1.
anonymous
 one year ago
If 5x^2 + y^4 = −9 then evaluate d^2y/dx^2 when x = 2 and y = 1.

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0implicit differentiation: \( \frac{d}{dx}(5x^2) + \frac{d}{dx}(y^4) = \frac{d}{dx}(9)\) you will get dy/dy at x = 2 and y = 1 from this. and then do it again to get second deriv at x = 2 and y = 1.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05x^2 + y^4 = −9 10x+4y^3y'=0

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\(5x^2 + y^4 = −9\) \(10x+4y^3y'=0\) gives you \(y'\) \(10+12y^2y'.y'+4y^3y'' = 10+12y^2(y')^2+4y^3y''=0\) gives you \(y''\)
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