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anonymous
 one year ago
The function H(t)=16t^2+vt+s shows the height H(t), in feet, of projectile launched vertically from s feet above the ground after t seconds. The initial speed is v feet per second.
Part A: The projectile was launched from a height of 82 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground.
Part B: What is the maximum height that the projectile will reach? Part C: Another object moves in the air along the path of g(t)=10+63.8t where g(t) is the height, in feet, of the object from the ground at time t second
anonymous
 one year ago
The function H(t)=16t^2+vt+s shows the height H(t), in feet, of projectile launched vertically from s feet above the ground after t seconds. The initial speed is v feet per second. Part A: The projectile was launched from a height of 82 feet with an initial velocity of 60 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. Part B: What is the maximum height that the projectile will reach? Part C: Another object moves in the air along the path of g(t)=10+63.8t where g(t) is the height, in feet, of the object from the ground at time t second

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, part A asked for an equaton, and i think it is 0=16t^2 + 50t + 90?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nevermind. I wil ask later;/
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