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anonymous
 one year ago
How can I simplify....
tan(arcsin x) ??
anonymous
 one year ago
How can I simplify.... tan(arcsin x) ??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep, so does it become... \[\frac{ \sin(\sin^{1} x) }{ \cos(\sin^{1} x) }\] ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then \[\frac{ x }{ \cos (\sin^{1}x) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that the furthest I can simplify?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do have any hints on what I can do?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Drawing triangle would be helpful.

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Let there be a triangle with opposite side of \(x\), and hypotenuse of \(1\). By Pythagorean Theorem, adjacent side would be \(\sqrt{1x^2}\). dw:1433108189889:dw From here, we can see that \(\sin\theta = \dfrac{x}{1} = x\), hence \(\theta = \arcsin(x)\) Now, what is \(\tan\theta = \tan(\arcsin(x))\)?

geerky42
 one year ago
Best ResponseYou've already chosen the best response.1Remember SOH CAH TOA?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh so tan is opposite/adjacent .... so \[\frac{ x }{ \sqrt{1x^2} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much @geerky42
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