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zzr0ck3r
 one year ago
For graphs \(G_0\) and \(G_1\) show that \(G_0\) is isomorphic to \(G_1\) if and only if there exists permutation matrix \(P\) such that \(P^{T}A_{G_0}P = A_{G_1}\) where \(A_{G_0}\) and \(A_{G_1}\) are the adjacency matricies for \(G_0\) and \(G_1\) respectively.
zzr0ck3r
 one year ago
For graphs \(G_0\) and \(G_1\) show that \(G_0\) is isomorphic to \(G_1\) if and only if there exists permutation matrix \(P\) such that \(P^{T}A_{G_0}P = A_{G_1}\) where \(A_{G_0}\) and \(A_{G_1}\) are the adjacency matricies for \(G_0\) and \(G_1\) respectively.

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zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0@geerky42 I cant msg you back... you are not a fan of me

zzr0ck3r
 one year ago
Best ResponseYou've already chosen the best response.0But yes I have had way harder things answered on this site, and this is actually linear algebra which many people here love. The question is posted on math stack exchange as well but the answer is not rigorous and they don't like when you repost questions even if the other thread is dead...
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