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anonymous
 one year ago
Simplify and identify the domain.
anonymous
 one year ago
Simplify and identify the domain.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433113440490:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[4x+8\neq 0,x \neq2\] \[x^29\neq0,x \neq \pm3\] Except these values all other real values of x are in domain.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@surjithayer sorry i was having computer problems!

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1To explain @surjithayer 's response, the domain of a rational function (function with polynomials in fractions) is all real except when the denominator becomes zero.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what is the next step to simplify the fraction? @mathmate

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Factor all expressions. Cancel common factors if applicable with condition (x\(\ne\)3, etc.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you think you can show me on the drawing tool, i understand better!!

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1I can give you an example, but bear with me for speed. \(f(x)=\frac{x+1}{x^21}\) Factor: \(f(x)=\frac{x+1}{(x+1)(x1)}\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1Cancel with condition that x\(\ne\)1 \(f(x)=\frac{1}{(x1)}\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.1The domain is x\(\ne\)1,1 (because of the original function)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we can cancel a and c?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you there? @mathmate
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