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anonymous

  • one year ago

Simplify and identify the domain.

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  1. anonymous
    • one year ago
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    |dw:1433113440490:dw|

  2. anonymous
    • one year ago
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    @pooja195

  3. anonymous
    • one year ago
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    \[4x+8\neq 0,x \neq-2\] \[x^2-9\neq0,x \neq \pm3\] Except these values all other real values of x are in domain.

  4. anonymous
    • one year ago
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    @surjithayer sorry i was having computer problems!

  5. anonymous
    • one year ago
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    @mathmate @geerky42

  6. mathmate
    • one year ago
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    To explain @surjithayer 's response, the domain of a rational function (function with polynomials in fractions) is all real except when the denominator becomes zero.

  7. anonymous
    • one year ago
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    so what is the next step to simplify the fraction? @mathmate

  8. mathmate
    • one year ago
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    Factor all expressions. Cancel common factors if applicable with condition (x\(\ne\)-3, etc.

  9. anonymous
    • one year ago
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    do you think you can show me on the drawing tool, i understand better!!

  10. anonymous
    • one year ago
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    @mathmate

  11. mathmate
    • one year ago
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    I can give you an example, but bear with me for speed. \(f(x)=\frac{x+1}{x^2-1}\) Factor: \(f(x)=\frac{x+1}{(x+1)(x-1)}\)

  12. mathmate
    • one year ago
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    Cancel with condition that x\(\ne\)-1 \(f(x)=\frac{1}{(x-1)}\)

  13. mathmate
    • one year ago
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    The domain is x\(\ne\)-1,1 (because of the original function)

  14. anonymous
    • one year ago
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    okay!

  15. anonymous
    • one year ago
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    we can cancel a and c?

  16. anonymous
    • one year ago
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    @mathmate

  17. anonymous
    • one year ago
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    @ganeshie8

  18. anonymous
    • one year ago
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    are you there? @mathmate

  19. mathmate
    • one year ago
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    what's a and c?

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