anonymous
  • anonymous
Simplify and identify the domain.
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
|dw:1433113440490:dw|
anonymous
  • anonymous
anonymous
  • anonymous
\[4x+8\neq 0,x \neq-2\] \[x^2-9\neq0,x \neq \pm3\] Except these values all other real values of x are in domain.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@surjithayer sorry i was having computer problems!
anonymous
  • anonymous
mathmate
  • mathmate
To explain @surjithayer 's response, the domain of a rational function (function with polynomials in fractions) is all real except when the denominator becomes zero.
anonymous
  • anonymous
so what is the next step to simplify the fraction? @mathmate
mathmate
  • mathmate
Factor all expressions. Cancel common factors if applicable with condition (x\(\ne\)-3, etc.
anonymous
  • anonymous
do you think you can show me on the drawing tool, i understand better!!
anonymous
  • anonymous
mathmate
  • mathmate
I can give you an example, but bear with me for speed. \(f(x)=\frac{x+1}{x^2-1}\) Factor: \(f(x)=\frac{x+1}{(x+1)(x-1)}\)
mathmate
  • mathmate
Cancel with condition that x\(\ne\)-1 \(f(x)=\frac{1}{(x-1)}\)
mathmate
  • mathmate
The domain is x\(\ne\)-1,1 (because of the original function)
anonymous
  • anonymous
okay!
anonymous
  • anonymous
we can cancel a and c?
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
are you there? @mathmate
mathmate
  • mathmate
what's a and c?

Looking for something else?

Not the answer you are looking for? Search for more explanations.