trantom
  • trantom
Please help! I have this worksheet due tomorrow and I don't want answers but I don't know what to do. I tried using right triangles but there aren't any I know enough about. I'll attach a drawing of the problem in the thread. Thanks!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
trantom
  • trantom
|dw:1433114484012:dw|
trantom
  • trantom
The 11 refers to \[LT\]
trantom
  • trantom
|dw:1433114690021:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ganeshie8
  • ganeshie8
what are you trying to find
trantom
  • trantom
The missing lengths sorry I should have said that xD
trantom
  • trantom
PT, PN, LR, and RT (the lengths of all these segments)
ganeshie8
  • ganeshie8
Okay what lengths are you given ?
trantom
  • trantom
They're labelled in the diagram
ganeshie8
  • ganeshie8
diagram is a bit confusing, can you write down the given lengths
trantom
  • trantom
But here LM=7 MN=8 TN=10 PR=3 RM=6 LT=11
trantom
  • trantom
|dw:1433114943288:dw|
ganeshie8
  • ganeshie8
you may use "intersecting chords theorem" to find RT
ganeshie8
  • ganeshie8
|dw:1433115060081:dw|
trantom
  • trantom
oh ok I get that
ganeshie8
  • ganeshie8
what do you get for RT ?
trantom
  • trantom
LR=9 RT=2
trantom
  • trantom
I got you man thanks so much!
trantom
  • trantom
Now what about PT, can I do the same thing for that?
ganeshie8
  • ganeshie8
how do you know its not LR = 2 RT = 9 ?
trantom
  • trantom
Because the two larger ones are always on the same side of the intersection
trantom
  • trantom
oh but it could be the other way too.. oh actually that's weird
trantom
  • trantom
oh I know
trantom
  • trantom
A triangle with side lengths 6, 7, and 2 is impossible right? wait not that's totally possible Agh I'm confused
trantom
  • trantom
oh because LR goes past the center and RT doesn't start until after that
ganeshie8
  • ganeshie8
maybe lets find PT first
trantom
  • trantom
thats a good idea xD
trantom
  • trantom
You could use a lot of trig to get angle LRM, then use its vertical angle PRT to find PT
ganeshie8
  • ganeshie8
there is an easy formula
ganeshie8
  • ganeshie8
simply use this |dw:1433115780042:dw|
trantom
  • trantom
so... 15x8=10(x-10) and x-10 is PT
ganeshie8
  • ganeshie8
shouldnt it be 15x8=10(x\(\color{red}{+}\)10) ?
trantom
  • trantom
if you want x to be pt then yes, but I was having x-10 be pt anyway I got pt=12
ganeshie8
  • ganeshie8
|dw:1433116168532:dw|
trantom
  • trantom
or x is 4 in yours
ganeshie8
  • ganeshie8
NT = 10 right ?
ganeshie8
  • ganeshie8
you should be getting PT=2 http://www.wolframalpha.com/input/?i=solve%208(8%2B7)%20%3D%2010(10%2Bx)&t=crmtb01
trantom
  • trantom
where did you get x+8 from? there's no 8 there
trantom
  • trantom
shouldn't it be 15*8 = 10(x+10)
ganeshie8
  • ganeshie8
sry it was a typo yeah it is `15*8 = 10(x+10)`
trantom
  • trantom
12= x+10 x=2 yep
trantom
  • trantom
Ok I get it thanks!
trantom
  • trantom
and the reason why LR=9 and RT=2 instead of LR=2 and RT=9 is because a triangle with side lengths 2, 3, and 9 is impossible!
ganeshie8
  • ganeshie8
Looks good!
trantom
  • trantom
Thank you so much I've been getting B+'s and A-'s on a couple tests lately I need to get back to being an A student xD
ganeshie8
  • ganeshie8
I see you're very good in geometry, you deserve A+

Looking for something else?

Not the answer you are looking for? Search for more explanations.