I need help with differentiating the following equation using implicit differentiation:
x^2 - 2xy + y^3 = 6

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do this
d/dx (x^2)
d/dx(2xy)
d/dx(y^3)
d/dx(6)

Right, so that gives me
2x - 2y - 2y'x + 3y^2y' = 0
correct?

right. Solve for y' and you're done

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