## A community for students. Sign up today

Here's the question you clicked on:

## anonymous one year ago I need help with differentiating the following equation using implicit differentiation: x^2 - 2xy + y^3 = 6

• This Question is Closed
1. anonymous

do this d/dx (x^2) d/dx(2xy) d/dx(y^3) d/dx(6)

2. anonymous

Right, so that gives me 2x - 2y - 2y'x + 3y^2y' = 0 correct?

3. anonymous

right. Solve for y' and you're done

4. anonymous

This is what I get when I solve for y' but apparently its incorrect... $y' = \frac{ 2y - 2x }{ 3y^2 - 2x }$

5. anonymous

You differentiated it right so it must be that you made an algebraic mistake somewhere when solving for y'. check again.

6. amistre64

the algebra seems fine

7. anonymous

Really? So do you think that's the correct answer?

8. amistre64

maybe the system they are using thinks it can be reduced

9. anonymous

Right... But I also put the equation into an online calculator and it gets ... $y' = \frac{ 2x-2y }{ 2x - 3y^2 }$

10. amistre64

you can factor a 2 out of the top, but i dont see much else for it

11. anonymous

I keep looking through my calculations and I still don't see anything wrong

12. amistre64

factoring out a -1/-1 is not that important

13. amistre64

2(x-y) for the top

14. anonymous

Does it change the answer when you factor out a -1/-1 ?

15. amistre64

it only changes form since -1/-1 = 1

16. amistre64

(a-b) = -(b-a)

17. anonymous

Right, so it wouldn't be a necessary step to take right?

18. amistre64

its not required to me

19. amistre64

x^2 - 2xy + y^3 = 6 2x x' - (2x'y+2xy') + 3y^2 y' = 0 x' = dx/dx = 1 2x - 2y -2x y' + 3y^2 y' = 0 2x - 2y + (3y^2-2x) y' = 0 2(x -y) + (3y^2-2x) y' = 0

20. amistre64

y' = 2(y-x)/(3y^2 - 2x)

21. anonymous

That's exactly what I did! So I don't think it should be wrong

22. amistre64

its not wrong according to what you have provided us. can you give a screen shot or picture?

23. anonymous

Of the question?

24. amistre64

perferably yes ...

25. anonymous

Sure

26. amistre64

and how many tries do you have to get it 'correct' ?

27. anonymous

It's unlimited

28. amistre64

oh that good lol

29. anonymous

Haha i know right xD

30. amistre64

screen shot it when you input 2(y-x)/(3y^2 - 2x)

31. anonymous

kk hold on

32. anonymous

Oh wow now its saying that it's correct >.< This is ridiculous lol

33. amistre64

i was going to see if you were missing a paranthesis :)

34. anonymous

I'm always cautious of the parentheses XD there was something wrong with the program, I'm sure :D lol

35. anonymous

Thanks so much though!

36. amistre64

good luck :)

37. anonymous

Thanks! :)

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy