At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

do this
d/dx (x^2)
d/dx(2xy)
d/dx(y^3)
d/dx(6)

Right, so that gives me
2x - 2y - 2y'x + 3y^2y' = 0
correct?

right. Solve for y' and you're done

the algebra seems fine

Really? So do you think that's the correct answer?

maybe the system they are using thinks it can be reduced

you can factor a 2 out of the top, but i dont see much else for it

I keep looking through my calculations and I still don't see anything wrong

factoring out a -1/-1 is not that important

2(x-y) for the top

Does it change the answer when you factor out a -1/-1 ?

it only changes form since -1/-1 = 1

(a-b) = -(b-a)

Right, so it wouldn't be a necessary step to take right?

its not required to me

y' = 2(y-x)/(3y^2 - 2x)

That's exactly what I did! So I don't think it should be wrong

its not wrong according to what you have provided us.
can you give a screen shot or picture?

Of the question?

perferably yes ...

Sure

and how many tries do you have to get it 'correct' ?

It's unlimited

oh that good lol

Haha i know right xD

screen shot it when you input
2(y-x)/(3y^2 - 2x)

kk hold on

Oh wow now its saying that it's correct >.< This is ridiculous lol

i was going to see if you were missing a paranthesis :)

Thanks so much though!

good luck :)

Thanks! :)