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anonymous
 one year ago
I need help with differentiating the following equation using implicit differentiation:
x^2  2xy + y^3 = 6
anonymous
 one year ago
I need help with differentiating the following equation using implicit differentiation: x^2  2xy + y^3 = 6

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do this d/dx (x^2) d/dx(2xy) d/dx(y^3) d/dx(6)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right, so that gives me 2x  2y  2y'x + 3y^2y' = 0 correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right. Solve for y' and you're done

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is what I get when I solve for y' but apparently its incorrect... \[y' = \frac{ 2y  2x }{ 3y^2  2x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You differentiated it right so it must be that you made an algebraic mistake somewhere when solving for y'. check again.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2the algebra seems fine

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Really? So do you think that's the correct answer?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2maybe the system they are using thinks it can be reduced

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right... But I also put the equation into an online calculator and it gets ... \[y' = \frac{ 2x2y }{ 2x  3y^2 }\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2you can factor a 2 out of the top, but i dont see much else for it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I keep looking through my calculations and I still don't see anything wrong

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2factoring out a 1/1 is not that important

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Does it change the answer when you factor out a 1/1 ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2it only changes form since 1/1 = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right, so it wouldn't be a necessary step to take right?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2its not required to me

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2x^2  2xy + y^3 = 6 2x x'  (2x'y+2xy') + 3y^2 y' = 0 x' = dx/dx = 1 2x  2y 2x y' + 3y^2 y' = 0 2x  2y + (3y^22x) y' = 0 2(x y) + (3y^22x) y' = 0

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2y' = 2(yx)/(3y^2  2x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's exactly what I did! So I don't think it should be wrong

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2its not wrong according to what you have provided us. can you give a screen shot or picture?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2and how many tries do you have to get it 'correct' ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Haha i know right xD

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2screen shot it when you input 2(yx)/(3y^2  2x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wow now its saying that it's correct >.< This is ridiculous lol

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2i was going to see if you were missing a paranthesis :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm always cautious of the parentheses XD there was something wrong with the program, I'm sure :D lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much though!
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