## matlee one year ago I have a question about angles, on how wide they can be

1. matlee

|dw:1433115942278:dw|

2. matlee

Hi triical i need help again on angles

3. triciaal

a straight line is an angle of 180 degrees

4. matlee

is there a way to know how wide a angle is?

5. matlee

If the box were 5 feet in length would i be able to tell how wide a angle would be directly in the middle?

6. matlee

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7. matlee

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8. triciaal

not sure if you are combining 2 examples or is the wall 5 ft from the weapon?

9. triciaal

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10. matlee

No the weapon is on the wall which is 5ft wide and only sprays 40 degree angle , and yes i am combining two examples

11. matlee

hmm no its more like i will draw your same example

12. matlee

|dw:1433116606778:dw|

13. jim_thompson5910

is it a top down, or birds eye view? |dw:1433116747233:dw| the circle is the top of the person's head

14. matlee

Birds eye i would say , its really a sprinkler i just want to check if i put this on a 40 degree angle to rotate would it hit the walls on each side or miss them?

15. triciaal

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16. matlee

omg

17. jim_thompson5910

I think it depends on how far the water can shoot out

18. matlee

Thanks for your help, i have many questions . Uhm lets just say its 35 feet long walls , would i be able to calculate that?

19. jim_thompson5910

do you know how far the water can shoot out? the max distance possible

20. matlee

my bad is shoots up to 38 feet but i can adjust it to 35 and the walls are 35 feet long

21. triciaal

sounds like you are going to consider the water pressure next

22. matlee

Yes lol

23. jim_thompson5910

you don't really need to use trig or anything like that you just need to make sure that the distance (shown below) is more than 38 feet to keep the wall dry |dw:1433117166966:dw|

24. jim_thompson5910

any other segment will be longer than 38 feet (assuming the black segment marked above is 38 feet) so if the black segment is say 40 feet, then the other segments are longer than 40 feet

25. matlee

|dw:1433117235149:dw| This is what it looks like

26. matlee

The water sprays from the point

27. jim_thompson5910

I see now

28. jim_thompson5910

where is that sprinkler point placed in relation to the 5 ft wall? At the halfway point?

29. matlee

yes, which makes me think it wont hit the walls but i have to make sure

30. matlee

directly next to the wall maybe 2 inches away

31. jim_thompson5910

ok against the wall, but where along the wall?

32. matlee

directly at the 2.5 length

33. jim_thompson5910

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34. jim_thompson5910

oh ok, thx

35. matlee

here i will draw what i have so far

36. matlee

oh nvm

37. matlee

Thanks for the help btw

38. jim_thompson5910

anyways, since the sprinkler is at the halfway point, we know this |dw:1433117543177:dw|

39. jim_thompson5910

I got the 34.833 from the fact that (35 ft ) - (2 inches) = (35 ft) - (0.167 ft) = 34.833 ft

40. matlee

Ok

41. jim_thompson5910

pull out this triangle |dw:1433117745200:dw|

42. jim_thompson5910

use the pythagorean theorem to solve for x

43. matlee

Ok

44. matlee

34.92=C

45. matlee

X

46. jim_thompson5910

good

47. jim_thompson5910

oh wait I'm not thinking one sec

48. matlee

yes cus 40 degrees

49. jim_thompson5910

I'm going to assume that the sprinkler is aimed in a way such that these angles (marked below) are congruent. Put another way, the sprinkler is watering each half equally |dw:1433118000730:dw|

50. matlee

yes

51. jim_thompson5910

if that is the case, then each of those angles are 70 degrees since 70+70+40 = 180

52. jim_thompson5910

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53. matlee

i just noticed theres no sprinklers that start in the middle and go left and right grr

54. jim_thompson5910

the water sprays at most 38 feet so the longest this segment (marked below) can get is 38 ft |dw:1433118100606:dw|

55. matlee

Yes

56. jim_thompson5910

The question is: is the marked segment below 2.5 feet? |dw:1433118160441:dw|

57. jim_thompson5910

IF the last segment marked was 2.5 ft, then a triangle would form |dw:1433118194993:dw| and this triangle would have its segment lying right against the wall

58. matlee

No its just if the water will ever hit the walls is my question

59. jim_thompson5910

I know. What I'm trying to say is that IF this horizontal segment of the triangle is 2.5 ft, then the triangle will lie along the right wall. Which means the water will hit the wall IF the horizontal segment is longer than 2.5 ft, then the water will hit the wall but will come much closer to the sprinkler

60. matlee

I am still confused, how would you be able to check, i know if bullets went straight forever theyd eventually hit a wall but the water only goes 38 feet. and dies out afterwards that length

61. jim_thompson5910

One moment. I'll try to paint a better picture

62. matlee

Sorry im not very comprehensive lols

63. matlee

and if i spelled comprehension in the wrong way i meant my comprehensions skills are below 0

64. matlee

hello?

65. matlee

;9

66. jim_thompson5910

I'm making a pic at the moment. one sec

67. matlee

Ok

68. jim_thompson5910

I'm making a geogebra applet so you can see an accurate diagram

69. matlee

Thanks so much! What is an applet?

70. jim_thompson5910

well ideally there is some level of interactivity, but I don't think that's needed here. Anyways, that would take longer than normal and I'm taking a long time as it is. So I'll just post a pic of what I have so far (see attached)

71. matlee

holy crap so it hits the wall nearly automatically

72. jim_thompson5910

anyways, in that diagram, the distance from S to P is 2.5 ft using a bit of trig, we can figure out that the distance from S to K is roughly 7.31 ft but the water can shoot as far as 38 ft, so the water will definitely hit the left & right walls

73. jim_thompson5910

yes it might be better to have the sprinkler set up halfway along the 35 ft wall then again, nvm it will still hit a wall since that 5 ft gap isn't that big

74. matlee

lols yeah ! Well i am very grateful for your help! Thank you! And Thanks again!

75. matlee

are you able to check at what degrees it doesnt hit the walls?

76. jim_thompson5910

you're welcome, I suggest you check out geogebra. It's not as great as something like autocad, but it allows for (somewhat) quick scale drawings to figure out the distances/lengths easily. And the program is free, so another bonus.

77. matlee

Ok i sure will, thatll be helpful for this project, autocad is somewhat like autodesk inventor?

78. jim_thompson5910

I've never heard of that other program, but perhaps? Autocad is mainly for use if you want to build blueprints or schematic drawings of objects (often in 3D).

79. matlee

Oh ok, i saw auto cad in my engineering class just never used it. Well i appreaciate your help, i have many other questions but i think i should close this one

80. jim_thompson5910

np