matlee
  • matlee
I have a question about angles, on how wide they can be
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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matlee
  • matlee
|dw:1433115942278:dw|
matlee
  • matlee
Hi triical i need help again on angles
triciaal
  • triciaal
a straight line is an angle of 180 degrees

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matlee
  • matlee
is there a way to know how wide a angle is?
matlee
  • matlee
If the box were 5 feet in length would i be able to tell how wide a angle would be directly in the middle?
matlee
  • matlee
|dw:1433116178824:dw|
matlee
  • matlee
|dw:1433116309613:dw|
triciaal
  • triciaal
not sure if you are combining 2 examples or is the wall 5 ft from the weapon?
triciaal
  • triciaal
|dw:1433120061769:dw|
matlee
  • matlee
No the weapon is on the wall which is 5ft wide and only sprays 40 degree angle , and yes i am combining two examples
matlee
  • matlee
hmm no its more like i will draw your same example
matlee
  • matlee
|dw:1433116606778:dw|
jim_thompson5910
  • jim_thompson5910
is it a top down, or birds eye view? |dw:1433116747233:dw| the circle is the top of the person's head
matlee
  • matlee
Birds eye i would say , its really a sprinkler i just want to check if i put this on a 40 degree angle to rotate would it hit the walls on each side or miss them?
triciaal
  • triciaal
|dw:1433120181309:dw|
matlee
  • matlee
omg
jim_thompson5910
  • jim_thompson5910
I think it depends on how far the water can shoot out
matlee
  • matlee
Thanks for your help, i have many questions . Uhm lets just say its 35 feet long walls , would i be able to calculate that?
jim_thompson5910
  • jim_thompson5910
do you know how far the water can shoot out? the max distance possible
matlee
  • matlee
my bad is shoots up to 38 feet but i can adjust it to 35 and the walls are 35 feet long
triciaal
  • triciaal
sounds like you are going to consider the water pressure next
matlee
  • matlee
Yes lol
jim_thompson5910
  • jim_thompson5910
you don't really need to use trig or anything like that you just need to make sure that the distance (shown below) is more than 38 feet to keep the wall dry |dw:1433117166966:dw|
jim_thompson5910
  • jim_thompson5910
any other segment will be longer than 38 feet (assuming the black segment marked above is 38 feet) so if the black segment is say 40 feet, then the other segments are longer than 40 feet
matlee
  • matlee
|dw:1433117235149:dw| This is what it looks like
matlee
  • matlee
The water sprays from the point
jim_thompson5910
  • jim_thompson5910
I see now
jim_thompson5910
  • jim_thompson5910
where is that sprinkler point placed in relation to the 5 ft wall? At the halfway point?
matlee
  • matlee
yes, which makes me think it wont hit the walls but i have to make sure
matlee
  • matlee
directly next to the wall maybe 2 inches away
jim_thompson5910
  • jim_thompson5910
ok against the wall, but where along the wall?
matlee
  • matlee
directly at the 2.5 length
jim_thompson5910
  • jim_thompson5910
|dw:1433117449091:dw|
jim_thompson5910
  • jim_thompson5910
oh ok, thx
matlee
  • matlee
here i will draw what i have so far
matlee
  • matlee
oh nvm
matlee
  • matlee
Thanks for the help btw
jim_thompson5910
  • jim_thompson5910
anyways, since the sprinkler is at the halfway point, we know this |dw:1433117543177:dw|
jim_thompson5910
  • jim_thompson5910
I got the 34.833 from the fact that (35 ft ) - (2 inches) = (35 ft) - (0.167 ft) = 34.833 ft
matlee
  • matlee
Ok
jim_thompson5910
  • jim_thompson5910
pull out this triangle |dw:1433117745200:dw|
jim_thompson5910
  • jim_thompson5910
use the pythagorean theorem to solve for x
matlee
  • matlee
Ok
matlee
  • matlee
34.92=C
matlee
  • matlee
X
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
oh wait I'm not thinking one sec
matlee
  • matlee
yes cus 40 degrees
jim_thompson5910
  • jim_thompson5910
I'm going to assume that the sprinkler is aimed in a way such that these angles (marked below) are congruent. Put another way, the sprinkler is watering each half equally |dw:1433118000730:dw|
matlee
  • matlee
yes
jim_thompson5910
  • jim_thompson5910
if that is the case, then each of those angles are 70 degrees since 70+70+40 = 180
jim_thompson5910
  • jim_thompson5910
|dw:1433118055561:dw|
matlee
  • matlee
i just noticed theres no sprinklers that start in the middle and go left and right grr
jim_thompson5910
  • jim_thompson5910
the water sprays at most 38 feet so the longest this segment (marked below) can get is 38 ft |dw:1433118100606:dw|
matlee
  • matlee
Yes
jim_thompson5910
  • jim_thompson5910
The question is: is the marked segment below 2.5 feet? |dw:1433118160441:dw|
jim_thompson5910
  • jim_thompson5910
IF the last segment marked was 2.5 ft, then a triangle would form |dw:1433118194993:dw| and this triangle would have its segment lying right against the wall
matlee
  • matlee
No its just if the water will ever hit the walls is my question
jim_thompson5910
  • jim_thompson5910
I know. What I'm trying to say is that IF this horizontal segment of the triangle is 2.5 ft, then the triangle will lie along the right wall. Which means the water will hit the wall IF the horizontal segment is longer than 2.5 ft, then the water will hit the wall but will come much closer to the sprinkler
matlee
  • matlee
I am still confused, how would you be able to check, i know if bullets went straight forever theyd eventually hit a wall but the water only goes 38 feet. and dies out afterwards that length
jim_thompson5910
  • jim_thompson5910
One moment. I'll try to paint a better picture
matlee
  • matlee
Sorry im not very comprehensive lols
matlee
  • matlee
and if i spelled comprehension in the wrong way i meant my comprehensions skills are below 0
matlee
  • matlee
hello?
matlee
  • matlee
;9
jim_thompson5910
  • jim_thompson5910
I'm making a pic at the moment. one sec
matlee
  • matlee
Ok
jim_thompson5910
  • jim_thompson5910
I'm making a geogebra applet so you can see an accurate diagram
matlee
  • matlee
Thanks so much! What is an applet?
jim_thompson5910
  • jim_thompson5910
well ideally there is some level of interactivity, but I don't think that's needed here. Anyways, that would take longer than normal and I'm taking a long time as it is. So I'll just post a pic of what I have so far (see attached)
matlee
  • matlee
holy crap so it hits the wall nearly automatically
jim_thompson5910
  • jim_thompson5910
anyways, in that diagram, the distance from S to P is 2.5 ft using a bit of trig, we can figure out that the distance from S to K is roughly 7.31 ft but the water can shoot as far as 38 ft, so the water will definitely hit the left & right walls
jim_thompson5910
  • jim_thompson5910
yes it might be better to have the sprinkler set up halfway along the 35 ft wall then again, nvm it will still hit a wall since that 5 ft gap isn't that big
matlee
  • matlee
lols yeah ! Well i am very grateful for your help! Thank you! And Thanks again!
matlee
  • matlee
are you able to check at what degrees it doesnt hit the walls?
jim_thompson5910
  • jim_thompson5910
you're welcome, I suggest you check out geogebra. It's not as great as something like autocad, but it allows for (somewhat) quick scale drawings to figure out the distances/lengths easily. And the program is free, so another bonus.
matlee
  • matlee
Ok i sure will, thatll be helpful for this project, autocad is somewhat like autodesk inventor?
jim_thompson5910
  • jim_thompson5910
I've never heard of that other program, but perhaps? Autocad is mainly for use if you want to build blueprints or schematic drawings of objects (often in 3D).
matlee
  • matlee
Oh ok, i saw auto cad in my engineering class just never used it. Well i appreaciate your help, i have many other questions but i think i should close this one
jim_thompson5910
  • jim_thompson5910
np

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