anonymous
  • anonymous
What is the length of CD? http://media.apexlearning.com/Images/201004/04/19ddb83b-92c7-4835-8ee0-d1c224289299.gif
Geometry
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
Can please someone help me with this one?
ganeshie8
  • ganeshie8
the triangles are similar, simply set up a proportion and solve x

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ganeshie8
  • ganeshie8
\[\large \dfrac{15-x}{x}=\dfrac{20}{5}\] solve \(x\)
anonymous
  • anonymous
oh ok thank you so once I solve it then that will be the answer right?
ganeshie8
  • ganeshie8
what do you get when you solve ?
anonymous
  • anonymous
Wait let me solve it
ganeshie8
  • ganeshie8
okie
anonymous
  • anonymous
I got 3.75. Is that right?
ganeshie8
  • ganeshie8
doesn't look correct try again
anonymous
  • anonymous
Okay
anonymous
  • anonymous
0.7?
ganeshie8
  • ganeshie8
\[\large \dfrac{15-x}{x}=\dfrac{20}{5} \] canceling common factor 5 on right hand side fraction gives \[\large \dfrac{15-x}{x}=\dfrac{4}{1}\] yes ?
anonymous
  • anonymous
Yes.
ganeshie8
  • ganeshie8
cross multiply and get \[15-x = 4x\]
ganeshie8
  • ganeshie8
add \(x\) both sides \[15 = 5x\]
anonymous
  • anonymous
Okay
anonymous
  • anonymous
so its 3
ganeshie8
  • ganeshie8
divide \(5\) both sides \[3=x\] which is same as \[x=3\]
anonymous
  • anonymous
Got it, thank you so much :)
ganeshie8
  • ganeshie8
yw

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