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  1. anonymous
    • one year ago
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    @ganeshie8

  2. anonymous
    • one year ago
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    Can please someone help me with this one?

  3. ganeshie8
    • one year ago
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    the triangles are similar, simply set up a proportion and solve x

  4. ganeshie8
    • one year ago
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    \[\large \dfrac{15-x}{x}=\dfrac{20}{5}\] solve \(x\)

  5. anonymous
    • one year ago
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    oh ok thank you so once I solve it then that will be the answer right?

  6. ganeshie8
    • one year ago
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    what do you get when you solve ?

  7. anonymous
    • one year ago
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    Wait let me solve it

  8. ganeshie8
    • one year ago
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    okie

  9. anonymous
    • one year ago
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    I got 3.75. Is that right?

  10. ganeshie8
    • one year ago
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    doesn't look correct try again

  11. anonymous
    • one year ago
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    Okay

  12. anonymous
    • one year ago
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    0.7?

  13. ganeshie8
    • one year ago
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    \[\large \dfrac{15-x}{x}=\dfrac{20}{5} \] canceling common factor 5 on right hand side fraction gives \[\large \dfrac{15-x}{x}=\dfrac{4}{1}\] yes ?

  14. anonymous
    • one year ago
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    Yes.

  15. ganeshie8
    • one year ago
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    cross multiply and get \[15-x = 4x\]

  16. ganeshie8
    • one year ago
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    add \(x\) both sides \[15 = 5x\]

  17. anonymous
    • one year ago
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    Okay

  18. anonymous
    • one year ago
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    so its 3

  19. ganeshie8
    • one year ago
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    divide \(5\) both sides \[3=x\] which is same as \[x=3\]

  20. anonymous
    • one year ago
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    Got it, thank you so much :)

  21. ganeshie8
    • one year ago
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    yw

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spraguer (Moderator)
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