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anonymous

  • one year ago

Simplify and identify the domain.

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  1. anonymous
    • one year ago
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    |dw:1433117123881:dw|

  2. mathslover
    • one year ago
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    You need to first factorize the denominator. Can you do it?

  3. anonymous
    • one year ago
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    i barley started to learn this, so would you mind leading me through it

  4. anonymous
    • one year ago
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    i will post the answer choices!

  5. mathslover
    • one year ago
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    Yeah, sure! No problem! See : I've denominator as : \((4x + 8).(x^2 - 9) \) I'll factorize both of them separately. \(4x + 8\) can be written as : \(4(x+2)\) ; Notice what I did... I just took 4 common from both the terms and I was left with (x+2). Clear with this part?

  6. anonymous
    • one year ago
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    @jagr2713

  7. anonymous
    • one year ago
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    |dw:1433124883261:dw|

  8. anonymous
    • one year ago
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    |dw:1433125682747:dw|

  9. anonymous
    • one year ago
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    @jagr2713

  10. anonymous
    • one year ago
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    the last choice should have a parenthesis at the end

  11. anonymous
    • one year ago
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    are you there? @jagr2713

  12. anonymous
    • one year ago
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    @peachpi

  13. anonymous
    • one year ago
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    Let's factor 4x + 8. What is the biggest number that goes into both 4 and 8?

  14. anonymous
    • one year ago
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    that divides into both of them? 4

  15. anonymous
    • one year ago
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    |dw:1433127777689:dw|

  16. anonymous
    • one year ago
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    |dw:1433127898204:dw|

  17. anonymous
    • one year ago
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    im kinda confused?

  18. anonymous
    • one year ago
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    have you done factoring yet in school?

  19. anonymous
    • one year ago
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    I'm only asking you to reduce the 2 fractions inside the parentheses right now

  20. anonymous
    • one year ago
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    do you know how to put 4/4 in lowest terms?

  21. anonymous
    • one year ago
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    not really!! and not i barley started learning to factor!

  22. anonymous
    • one year ago
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    the question you posted is relatively advanced algebra. I'm not really sure how to help you if you aren't even familiar with the basic stuff. :(

  23. anonymous
    • one year ago
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    well it is a worksheet that we are suppose to get help with to start becoming familiar with this topic!

  24. anonymous
    • one year ago
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    @peachpi can you just try to walk through it with me? please!!

  25. anonymous
    • one year ago
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    |dw:1433128688437:dw|

  26. anonymous
    • one year ago
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    does that make sense?

  27. anonymous
    • one year ago
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    oh okay so the cancel out!

  28. anonymous
    • one year ago
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    yes. now to factor x² - 9. There is no common factor, so we have to use another rule. What number times itself is 9?

  29. anonymous
    • one year ago
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    in other words, what's the square root of 9?

  30. anonymous
    • one year ago
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    3

  31. anonymous
    • one year ago
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    this rule is called a difference of squares. x² - 9 = (x - 3)(x + 3)

  32. anonymous
    • one year ago
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    okay!

  33. anonymous
    • one year ago
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    so then it whould equal to zero?

  34. anonymous
    • one year ago
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    so 3 and -3?

  35. anonymous
    • one year ago
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    yes. but you also have to do 4x+8 = 0

  36. anonymous
    • one year ago
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    ok

  37. anonymous
    • one year ago
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    how do i do that one?

  38. anonymous
    • one year ago
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    start by subtracting 8 from both sides

  39. anonymous
    • one year ago
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    |dw:1433129376428:dw|

  40. anonymous
    • one year ago
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    4x=-8

  41. anonymous
    • one year ago
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    how do you get x by itself from there?

  42. anonymous
    • one year ago
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    |dw:1433129414498:dw|

  43. anonymous
    • one year ago
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    |dw:1433129573453:dw|

  44. anonymous
    • one year ago
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    |dw:1433129604736:dw|

  45. anonymous
    • one year ago
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    |dw:1433129767322:dw|

  46. anonymous
    • one year ago
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    so your answers for the exclusions \[x \neq -3, -2, 3\]

  47. anonymous
    • one year ago
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    okay!

  48. anonymous
    • one year ago
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    now let's get back to the simplifying part. I'm going to rewrite the expression to show the factoring

  49. anonymous
    • one year ago
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    so as of now the possible answers are b and d! correct?

  50. anonymous
    • one year ago
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    yes

  51. anonymous
    • one year ago
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    okay!

  52. anonymous
    • one year ago
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    |dw:1433130093957:dw|

  53. anonymous
    • one year ago
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    |dw:1433130238835:dw| is this right?

  54. anonymous
    • one year ago
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    |dw:1433130292264:dw|

  55. anonymous
    • one year ago
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    @peachpi

  56. anonymous
    • one year ago
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    is my simplifying correct?

  57. anonymous
    • one year ago
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    that's right :)

  58. anonymous
    • one year ago
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    so b?

  59. anonymous
    • one year ago
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    yes

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