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You need to first factorize the denominator. Can you do it?
i barley started to learn this, so would you mind leading me through it
i will post the answer choices!
Yeah, sure! No problem! See : I've denominator as : \((4x + 8).(x^2 - 9) \) I'll factorize both of them separately. \(4x + 8\) can be written as : \(4(x+2)\) ; Notice what I did... I just took 4 common from both the terms and I was left with (x+2). Clear with this part?
the last choice should have a parenthesis at the end
are you there? @jagr2713
Let's factor 4x + 8. What is the biggest number that goes into both 4 and 8?
that divides into both of them? 4
im kinda confused?
have you done factoring yet in school?
I'm only asking you to reduce the 2 fractions inside the parentheses right now
do you know how to put 4/4 in lowest terms?
not really!! and not i barley started learning to factor!
the question you posted is relatively advanced algebra. I'm not really sure how to help you if you aren't even familiar with the basic stuff. :(
well it is a worksheet that we are suppose to get help with to start becoming familiar with this topic!
@peachpi can you just try to walk through it with me? please!!
does that make sense?
oh okay so the cancel out!
yes. now to factor x² - 9. There is no common factor, so we have to use another rule. What number times itself is 9?
in other words, what's the square root of 9?
this rule is called a difference of squares. x² - 9 = (x - 3)(x + 3)
so then it whould equal to zero?
so 3 and -3?
yes. but you also have to do 4x+8 = 0
how do i do that one?
start by subtracting 8 from both sides
how do you get x by itself from there?
so your answers for the exclusions \[x \neq -3, -2, 3\]
now let's get back to the simplifying part. I'm going to rewrite the expression to show the factoring
so as of now the possible answers are b and d! correct?
|dw:1433130238835:dw| is this right?
is my simplifying correct?
that's right :)