anonymous
  • anonymous
simplify x/7x+x^2 answer choices: 1/7x+x; where x≠-7 1/7x; where x≠0 1/7+x; where x≠0, -7 1/7
Mathematics
katieb
  • katieb
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Nnesha
  • Nnesha
factor denominator
anonymous
  • anonymous
btw these are all fraction
anonymous
  • anonymous
and i know how to simplify it, but why does it have the: where x≠??

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Nnesha
  • Nnesha
alright what did you get at the denominator 7x+x^2 = ?
anonymous
  • anonymous
x(x+7) ?
anonymous
  • anonymous
wait, x+7?
Nnesha
  • Nnesha
yep right now set it like this \[\huge\rm x(x+7) \cancel{=}0\] denominator can't be equal to 0 bec when you can't divide anything by 0 x/0 = undefined
Nnesha
  • Nnesha
\[\huge\rm x(x+7) \cancel{=}0\] solve for x
Nnesha
  • Nnesha
set both x and (x+7)not equal to 0 \[x \cancel{=} 0 , (x+7) \cancel{=} 0\] x can't be equal to 0 \[ \ (x+7) \cancel{=} 0\] solve for x^
anonymous
  • anonymous
so when it says x≠, i just have to put the numbers that come after is in for x in the equation and see if it works itself out or not?
Nnesha
  • Nnesha
well x≠something for example lest's say x≠ 6 that's mean xcan't be equal to 6 bec x- 6 when u plug in 6 for x you will get 0 6-6 = 0 that's what we don't want DENOMINATOR can't be equal to 0
anonymous
  • anonymous
ohhhhhhh okay... thank you soooo much!
Nnesha
  • Nnesha
np :-)

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