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anonymous

  • one year ago

simplify x/7x+x^2 answer choices: 1/7x+x; where x≠-7 1/7x; where x≠0 1/7+x; where x≠0, -7 1/7

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  1. Nnesha
    • one year ago
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    factor denominator

  2. anonymous
    • one year ago
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    btw these are all fraction

  3. anonymous
    • one year ago
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    and i know how to simplify it, but why does it have the: where x≠??

  4. Nnesha
    • one year ago
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    alright what did you get at the denominator 7x+x^2 = ?

  5. anonymous
    • one year ago
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    x(x+7) ?

  6. anonymous
    • one year ago
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    wait, x+7?

  7. Nnesha
    • one year ago
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    yep right now set it like this \[\huge\rm x(x+7) \cancel{=}0\] denominator can't be equal to 0 bec when you can't divide anything by 0 x/0 = undefined

  8. Nnesha
    • one year ago
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    \[\huge\rm x(x+7) \cancel{=}0\] solve for x

  9. Nnesha
    • one year ago
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    set both x and (x+7)not equal to 0 \[x \cancel{=} 0 , (x+7) \cancel{=} 0\] x can't be equal to 0 \[ \ (x+7) \cancel{=} 0\] solve for x^

  10. anonymous
    • one year ago
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    so when it says x≠, i just have to put the numbers that come after is in for x in the equation and see if it works itself out or not?

  11. Nnesha
    • one year ago
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    well x≠something for example lest's say x≠ 6 that's mean xcan't be equal to 6 bec x- 6 when u plug in 6 for x you will get 0 6-6 = 0 that's what we don't want DENOMINATOR can't be equal to 0

  12. anonymous
    • one year ago
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    ohhhhhhh okay... thank you soooo much!

  13. Nnesha
    • one year ago
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    np :-)

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