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anonymous
 one year ago
simplify x/7x+x^2
answer choices:
1/7x+x; where x≠7
1/7x; where x≠0
1/7+x; where x≠0, 7
1/7
anonymous
 one year ago
simplify x/7x+x^2 answer choices: 1/7x+x; where x≠7 1/7x; where x≠0 1/7+x; where x≠0, 7 1/7

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw these are all fraction

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and i know how to simplify it, but why does it have the: where x≠??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1alright what did you get at the denominator 7x+x^2 = ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yep right now set it like this \[\huge\rm x(x+7) \cancel{=}0\] denominator can't be equal to 0 bec when you can't divide anything by 0 x/0 = undefined

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm x(x+7) \cancel{=}0\] solve for x

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1set both x and (x+7)not equal to 0 \[x \cancel{=} 0 , (x+7) \cancel{=} 0\] x can't be equal to 0 \[ \ (x+7) \cancel{=} 0\] solve for x^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so when it says x≠, i just have to put the numbers that come after is in for x in the equation and see if it works itself out or not?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well x≠something for example lest's say x≠ 6 that's mean xcan't be equal to 6 bec x 6 when u plug in 6 for x you will get 0 66 = 0 that's what we don't want DENOMINATOR can't be equal to 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhhhhhh okay... thank you soooo much!
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