## anonymous one year ago simplify x/7x+x^2 answer choices: 1/7x+x; where x≠-7 1/7x; where x≠0 1/7+x; where x≠0, -7 1/7

1. Nnesha

factor denominator

2. anonymous

btw these are all fraction

3. anonymous

and i know how to simplify it, but why does it have the: where x≠??

4. Nnesha

alright what did you get at the denominator 7x+x^2 = ?

5. anonymous

x(x+7) ?

6. anonymous

wait, x+7?

7. Nnesha

yep right now set it like this $\huge\rm x(x+7) \cancel{=}0$ denominator can't be equal to 0 bec when you can't divide anything by 0 x/0 = undefined

8. Nnesha

$\huge\rm x(x+7) \cancel{=}0$ solve for x

9. Nnesha

set both x and (x+7)not equal to 0 $x \cancel{=} 0 , (x+7) \cancel{=} 0$ x can't be equal to 0 $\ (x+7) \cancel{=} 0$ solve for x^

10. anonymous

so when it says x≠, i just have to put the numbers that come after is in for x in the equation and see if it works itself out or not?

11. Nnesha

well x≠something for example lest's say x≠ 6 that's mean xcan't be equal to 6 bec x- 6 when u plug in 6 for x you will get 0 6-6 = 0 that's what we don't want DENOMINATOR can't be equal to 0

12. anonymous

ohhhhhhh okay... thank you soooo much!

13. Nnesha

np :-)