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anonymous
 one year ago
Hey! I really need help on this :( I will fan and medal.
Using the equation below as a model, fill in numbers in the place of a and b to create a rational equation that has an extraneous solution.
(x + a)/ax = b/x
Part 1. Show all work to solve for x in the equation and check the solution.
Part 2. Explain how to identify the extraneous solution and what it means.
anonymous
 one year ago
Hey! I really need help on this :( I will fan and medal. Using the equation below as a model, fill in numbers in the place of a and b to create a rational equation that has an extraneous solution. (x + a)/ax = b/x Part 1. Show all work to solve for x in the equation and check the solution. Part 2. Explain how to identify the extraneous solution and what it means.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't necessarily want an answer I just want someone to work it out with me :)

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{x+a}{ax}=\frac{b}{x}\rightarrow Is \quad this?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Um, I think you're asking me what values I plugged in for a and b. Here: a = 3 and b = 1.

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2First, remember, "x" must be different of zero, ok?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok :) so that means if I work it out for x and it comes out to x = 0 then it is not a solution, correct?

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2If x=0, both denominators of fractions become null and the equation will be indefined, or better, there is no solution.

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2Item "I.", ok? \[\frac{x+a}{ax}=\frac{b}{x}\rightarrow \frac{x+a=ab}{ax} \rightarrow \]Do you understand so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, I'm sorry but I do not understand... Also, my question says that I need to come up with some values for a and b. So, I think I might need to put those values in before I start working it out :) my values are: a = 3 and b = 1

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2Why your values are a=3 and b=1? These values are in the question.... but if "yes", it's simpler... replace these values in the equation, directly... look

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{x+a}{ax}=\frac{b}{x}\rightarrow \frac{x+3}{3x}=\frac{1}{x} \rightarrow\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@itsdaniela @raiders88 @Twetapoo @bishop.courtney2014 @Hero @amistre64 @ganeshie8 @saifoo.khan @paki @wio @Preetha

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2And solve the equation for x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I still do not know how to figure that out. I guess cross multiply?

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2Yes, look: \[\frac{x+3}{3x}=\frac{1}{x} \rightarrow x(x+3)=3x.1 \rightarrow ok?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so I would come out with x^2 + 3x = 3x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But then it would be x^2 = 0... I don't think that is correct.

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2This is the cross multiply, ok? So, if x^2 +3x = 3x, or ??? Look

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand. I think you subtract the 3x from each side...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which would leave you with x^2 = 0 but then you can't take the square root of 0 so I'm not sure what to do next. But is that what extraneous means?

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2Remember, when I said that "x" must be different of zero? And now, your solução is exactly zero? This is an inconsistency solution, so, to a=3 and b=1, this equation has no solution.... ok.... but x^2 is a quadratic function, whose graph is a parabola, remember?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Umm, I don't understand.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You don't have to help me if you don't want to, I know that this is probably very frustrating. I'm sorry that I stink at math lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But thank you for your time :) I will medal :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, thanks @netlopes1

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2Ok, but I will try again, ok?

netlopes1
 one year ago
Best ResponseYou've already chosen the best response.2It's no excuse, but my English is terrible (I'm Brazilian) and mathematics nomenclature is hard for me .... but I promise I will improve and I never give up ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's fine :) I'm just not good at math. Yes! It is always good to never give up! Always try your very best :) and if you have done your best, that's all that matters. Thanks again! And I finally figured it out :)
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