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I don't necessarily want an answer I just want someone to work it out with me :)

\[\frac{x+a}{ax}=\frac{b}{x}\rightarrow Is \quad this?\]

Um, I think you're asking me what values I plugged in for a and b. Here: a = 3 and b = 1.

First, remember, "x" must be different of zero, ok?

\[\frac{x+a}{ax}=\frac{b}{x}\rightarrow \frac{x+3}{3x}=\frac{1}{x} \rightarrow\]

Ok :)

And solve the equation for x

But I still do not know how to figure that out. I guess cross multiply?

Yes, look: \[\frac{x+3}{3x}=\frac{1}{x} \rightarrow x(x+3)=3x.1 \rightarrow ok?\]

Ok, so I would come out with x^2 + 3x = 3x?

But then it would be x^2 = 0... I don't think that is correct.

This is the cross multiply, ok? So, if x^2 +3x = 3x, or ??? Look

I don't understand. I think you subtract the 3x from each side...

Umm, I don't understand.

But thank you for your time :) I will medal :)

Ok, thanks @netlopes1

Ok, but I will try again, ok?