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anonymous

  • one year ago

Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y = x2 – 12x + 12 (Points : 4) 1 point in common; vertex on x-axis 2 points in common; vertex below x-axis 2 points in common; vertex above x-axis no points in common; vertex above x-axis

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  1. anonymous
    • one year ago
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    @KathyMae95

  2. anonymous
    • one year ago
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    Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 1 = 0 (Points : 4) three real-number roots two real-number roots one real-number root no real-number roots and then theres this one

  3. anonymous
    • one year ago
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    brb

  4. netlopes1
    • one year ago
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    please, how is the question: x^2 -12x + 12 or 3x^2 - 6x +1?

  5. anonymous
    • one year ago
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    because and can be idiot. how else. idk why they made it like that

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