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anonymous

  • one year ago

without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y=4x^2-12x+12 A. 2 points in common; vertex below x-axis B. no points in common; vertex above x-axis C. 1 point in common; vertex on x-axis D. 2 points in common; vertex above x-axis

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  1. anonymous
    • one year ago
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    @peachpi

  2. anonymous
    • one year ago
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    Calculate the discriminant.

  3. anonymous
    • one year ago
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    x^2 - x + 2 = 0 the discriminant is b²-4ac when you have ax²+bx+c therefore, you have a=1, b=-1, c=2, and b²-4ac = (-1)² - 4(1)(2) = 1 - 8 = -7

  4. anonymous
    • one year ago
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    make since?

  5. anonymous
    • one year ago
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    thats a exsample just to help you understand. here let me solve for your problem

  6. anonymous
    • one year ago
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    Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y = 4x^2 - 12x + 12 y = 4(x² - 3x) + 12 y = 4(x² - 3x + 3/4) + 12 - 3 y = 4(x - 3/2)² + 9 vertex: (3/2, 9) no points in common; vertex above x-axis

  7. anonymous
    • one year ago
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    So your answer would be B

  8. anonymous
    • one year ago
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    does this make since @yayah2001 ?

  9. anonymous
    • one year ago
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    thank you, I understand a lot better now.

  10. anonymous
    • one year ago
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    Np! :D

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spraguer (Moderator)
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