## anonymous one year ago compute the modulus and argument of each complex number. a) 1+i

1. anonymous

@mathmate could you help with this one?

2. zepdrix

Eyyy :) So what are we having trouble with? The modulus is just the length directly to that point, ya? So like,|dw:1433125698294:dw|

3. zepdrix

|dw:1433125748356:dw|So we have this going on, ya? :)

4. zepdrix

Mmm sorry sloppy hand writing -_- that's a $$\Large\rm |z|$$ on the graph

5. zepdrix

Or if you're more comfortable looking at it in polar form, you can do the steps to convert it into $$\Large\rm z=r e^{i\theta}$$ Where our modulus is r, and argument is the angle theta, err principle argument at least. Mmmmm what are you thinking ms Hailey? :d

6. anonymous

I got sqrt 2 for my modulus and pi/4 for my argument

7. anonymous

@zepdrix

8. zepdrix

yayyyy good job \c:/ do they just want pi/2 for the arg z? Or do they want the rotations and stuff also? so maybe pi/2 + 2k pi. I dunno i can't remember >.<

9. zepdrix

The principle argument, yes, is $$\Large\rm \frac{\pi}{4}$$. But notice that $$\Large\rm \frac{5\pi}{4}$$ is also an acceptable angle, I just spun a full time around the circle and landed in the same spot. If you haven't talked about that in your class, maybe we shouldn't worry about it :)

10. zepdrix

9pi/4, not 5pi/4, woops* bah anyway

11. anonymous

You are right! Thank you!