Differentiate: f(x)=x^5/2e^x i got (1/2)e^x x^3/2 (2x+5) is that right?

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Differentiate: f(x)=x^5/2e^x i got (1/2)e^x x^3/2 (2x+5) is that right?

Mathematics
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the exponential is in the denominator with the 5 or no?:) oh oh oh, it's x^(5/2)
\[\Large\rm f(x)=x^{5/2}e^x\]This?
Hmm yah looks correct, maybe a little over simplified though hehe.

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product rule... if that's really the question?!!?!?!??!
this is frustrating... can you draw the question?!
|dw:1433130619166:dw|
could be quotient rule... product rule... I have no idea.. I think everyone needs to learn Latex...I can see why people at stackexchange go nuts sometimes.
yeah thats it! sorry!! lol
which..?
@freckles more esp needed? another example of the conversation this morning
the drawing is correct
what tricaal wrote is the right one.
wait no hold on ill draw it
ok... that would be great. we all confused here.
|dw:1433138019813:dw|
Yes, the one I posted. So your solution is correct.
oh sorry i just kept scrolling down okay great thanks!!
I think he went a bit overboard. |dw:1433127295354:dw| where did you get the 2x+5 in your answer?
im looking at my notes but now i cant figure it out
hmmm even wolfram agrees with you.. must be some ... oh of course. your answer is a factored out version of what I have.
yeah it's fine... both answers are correct... it's just that one extra step which is factoring like terms came into play here. I though I lost my mind for a sec lol
you can factor the smallest x, e^x, and a 1/2 out ... that's what happened...when I distributed those things. I got my answer.
yeah jaja, but on my hw i think i didnt need to factor everything out, so i got confused
normally you don't have to... you could if you want. but an unfactored version
sorry os messed up an unfacrtored version of an answer is just as good as a factored version

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