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if we can not give out direct answers that would be great! ... At least show it's really B for the equation \[y=x^2+2x-24\] notice that the middle term is 2 and the last term is -24 so we need to find what two numbers we need to produce a positive 2
all possible combinations of 24 are
thank goodness for multiple choice, so we can use the
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since or equation patter is a + and - we need to figure out which number has to be negative and which number has to be positive in order to achieve 2x and - 24
*our equation pattern... sorry typing fast
I think that -4 and 6 will be perfect.. because of 2 reasons..
we know that (-4)(6) = -24
and -4+6 = 2
so now by factoring
we can check using the FOIL method and it does come back to the original equation that we had earlier.
to find our 0's we can just let y be 0 and solve for x. I think you could handle it from here
It's like trying to ask yourself what x value do I need for this to hold true.
@Caylahill do you want me to go further or can you handle 0=(x-4)(x+6) and find all x's ?
you can just use inspection and see that there are 2 x values that will make the equation 0