## anonymous one year ago The polar coordinates of a point are given. Find the rectangular coordinates of each point. (5,(π / 4)) (-2,(π / 6))

1. johnweldon1993

Or instead of going the long way backwards...we can also know that $\large x = rcos(\theta)$ and $\large y = rsin(\theta)$

2. johnweldon1993

So for example with your first point up there $\large x = 5cos(\pi/4)$ $\large y = 5sin(\pi/4)$

3. anonymous

And I can do the same for the second equation @johnweldon1993

4. johnweldon1993

Correct indeed :)

5. anonymous

so $x=-2(\cos(\pi/6)$

6. johnweldon1993

I just deleted the first post I made so as not to confuse you...why go a long way when there are shortcuts! lol And yes that is correct for your x-coordinate!

7. anonymous

Thank you so much @johnweldon1993 !

8. johnweldon1993

Anytime!

9. anonymous

@Johnweldon1993 is it weird that when I go to convert the first they come out to be the same point?

10. johnweldon1993

Not weird at all :P Seeing as how $$\large sin(45) = cos(45)$$ :)

11. anonymous

Ah, thank you! All this polar stuff is just alsfjasflkajlfa! @johnweldon1993

12. johnweldon1993

Lol it will come much easier dont worry :) Actually polar is the easiest of the bunch...wait till you get to cylindrical and spherical THOSE are the best ;) haha

13. anonymous

So I'm off to go dig my shallow grave.

14. johnweldon1993

Lol well if you are in DE right now, you wont deal with them any if at all...Calc 3 is where that comes into play :) So nope, stay above ground...for now :P lol no try and stay permanently lol :D