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anonymous
 one year ago
The polar coordinates of a point are given. Find the rectangular coordinates of each point.
(5,(π / 4))
(2,(π / 6))
anonymous
 one year ago
The polar coordinates of a point are given. Find the rectangular coordinates of each point. (5,(π / 4)) (2,(π / 6))

This Question is Closed

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Or instead of going the long way backwards...we can also know that \[\large x = rcos(\theta)\] and \[\large y = rsin(\theta)\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0So for example with your first point up there \[\large x = 5cos(\pi/4)\] \[\large y = 5sin(\pi/4)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And I can do the same for the second equation @johnweldon1993

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Correct indeed :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so \[x=2(\cos(\pi/6)\]

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0I just deleted the first post I made so as not to confuse you...why go a long way when there are shortcuts! lol And yes that is correct for your xcoordinate!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much @johnweldon1993 !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Johnweldon1993 is it weird that when I go to convert the first they come out to be the same point?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Not weird at all :P Seeing as how \(\large sin(45) = cos(45)\) :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, thank you! All this polar stuff is just alsfjasflkajlfa! @johnweldon1993

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Lol it will come much easier dont worry :) Actually polar is the easiest of the bunch...wait till you get to cylindrical and spherical THOSE are the best ;) haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I'm off to go dig my shallow grave.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Lol well if you are in DE right now, you wont deal with them any if at all...Calc 3 is where that comes into play :) So nope, stay above ground...for now :P lol no try and stay permanently lol :D
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