anonymous
  • anonymous
Given the geometric sequence 3, 6, 12, 24, …, what is a1, the first term? What is r, the common ratio? Find the 8th term of this sequence. What formula did you use? Be sure to show your work.
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

johnweldon1993
  • johnweldon1993
\(\large a_1 = 3\) this is the first number in your sequence r, hint* What number do you need to multiply to each previous number to get to the next?
anonymous
  • anonymous
can you explain more
johnweldon1993
  • johnweldon1993
Alright, so that a1 was pretty self explanatory so I'm assuming you have that! lol So the 'r' the common ratio We multiply each number by this 'r' to get to the following number Here the sequence is 3,6,12,24 right? To get from 3 to 6...what number do we multiply by?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
2
johnweldon1993
  • johnweldon1993
Right, so our common ratio is 2 Just to check it is consistent To get from 6 to 12 we also multiply by 2 and to get from 12 to 24 we again multiply by 2 Okay so good, we have our a1 and our 'r' Now we need to find the 8th term right?
anonymous
  • anonymous
yep
johnweldon1993
  • johnweldon1993
Alright, so then to find any term of a geometric sequence, we use the formula \[\large a_n = a_1 \times r^{n-1}\] So here, since we want the 8th term...we simply plug in 8 for 'n'...still 2 for 'r' and still 3 for 'a1' so we have \[\large a_8 = 3\times 2^{8-1}\] \[\large a_8 = 3\times 2^{7} = ?\]
anonymous
  • anonymous
384
johnweldon1993
  • johnweldon1993
And that is correct!
anonymous
  • anonymous
thats it?
anonymous
  • anonymous
thanks
johnweldon1993
  • johnweldon1993
Yeah that is it! No problem!
anonymous
  • anonymous
can you help me with another problem?

Looking for something else?

Not the answer you are looking for? Search for more explanations.