## zepdrix one year ago Better put your Poojamas on! It's Study Time!!!

1. zepdrix

|dw:1433131922743:dw| @pooja195

2. pooja195

LOL

3. zepdrix

So what's going on now? Factoring?

4. zepdrix

Or other stuff?

5. pooja195

its the same fraction stuff

6. zepdrix

fraction stuff? like this?$\Large\rm \frac{x}{x+1}=\frac{-4}{x}$solve for x? :O

7. pooja195

x*x=x^2 -4(x+1)=-4x-4 x^2=-4x-4 add to put everything on the same side as the x^2 x^2+4x+4=0 (x+2)(x+2) x=-2

8. zepdrix

yay good job \c:/

9. zepdrix

so that one was cake? what are we having trouble with then? <.< hmm

10. pooja195

just need some practice :P

11. pooja195

to figure out what I don't get :P so u can explain ofc

12. zepdrix

oh oh oh i remember.

13. zepdrix

$\Large\rm \frac{16x^2}{21x+7}\div\frac{4x^2-4x}{7x-7}$This one is kinda tough :o lemme know where you get stuck.

14. zepdrix

@pooja195 do you think you can finish this last one? :)

15. pooja195

Ok :/ $\huge~1)~~\frac{ 16x^2 }{ 21x+7}\times \frac{ 7x-7 }{ 4x^2-4x }$ $\huge~2)~\frac{ 16x^2 }{ 7(3x+1) }\times \frac{ 7(x-1) }{ 4x(x-1) }$

16. pooja195

@zepdrix :)

17. zepdrix

Ok good, now cancel stuff out if you can :)

18. zepdrix

Wow that is some big font +_+ lol

19. pooja195

Me like BIG > :) $\huge~\frac{ 16x^2 }{ 7(3x+1) }\times \frac{ 7 }{ 4x }=\frac{ ;-; }{ ;-; }$

20. zepdrix

lol, cancel moar

21. zepdrix

lots moar

22. pooja195

You cant cancel anymore! :/

23. pooja195

$\huge~\frac{ 16x^2 }{ (3x+1) }\times \frac{ }{ 4x }=\frac{ ;-; }{ ;-; }$

24. pooja195

:/

25. zepdrix

what happens when you divide the 7's out? What are you left with up there? Hint: It's not a zero. Dividing doesn't give you 0.

26. pooja195

1

27. zepdrix

$\Large\rm =\frac{16x^2}{3x+1}\cdot\frac{1}{4x}$Mmm k sounds right so far. MOAR

28. pooja195

Theres no more!

29. zepdrix

16 has a 4 in it. x^2 has an x in it.

30. zepdrix

There is moar.

31. pooja195

$\Huge~\frac{ (x+4)(x-4) }{ 3x+1 }\times \frac{ 1 }{ 4x }$ NO MORE.

32. pooja195

see

33. zepdrix

woah what in the world..?

34. zepdrix

break down the 16. 16 = ? x ?

35. pooja195

4x^2 ?

36. pooja195

wait no

37. pooja195

4x

38. zepdrix

what..? 16 = what times what

39. pooja195

4 times 4

40. zepdrix

$\Large\rm =\frac{16x^2}{3x+1}\cdot\frac{1}{4x}\quad=\quad\frac{4\cdot4x^2}{3x+1}\cdot\frac{1}{4x}$Good :o and x^2 is x times x, ya?

41. pooja195

O_o

42. zepdrix

$\Large\rm =\frac{4\cdot4\cdot x\cdot x }{3x+1}\cdot\frac{1}{4x}$

43. pooja195

Oh ok that makes sense ....

44. pooja195

I cant cancel more :/

45. pooja195

im consfused .-.

46. zepdrix

$\Large\rm =\frac{\color{red}{4}\cdot4\cdot x\cdot x }{3x+1}\cdot\frac{1}{\color{red}{4}x}$MOOAEERRRRR

47. zepdrix

$\Large\rm =\frac{\color{red}{4}\cdot4\cdot x\cdot \color{royalblue}{x} }{3x+1}\cdot\frac{1}{\color{red}{4}\color{royalblue}{x}}$MOER MOAR MOARRRR

48. pooja195

$\huge~\frac{ 4x }{ 3x+1}~$

49. pooja195

WAIT DONT SAY IT

50. pooja195

51. zepdrix

4x/(3x+1) ? ooo good job \c:/

52. pooja195

-_- smh

53. zepdrix

You're having a lot of trouble breaking these things down, we have to do more :(

54. zepdrix

Simplify:$\Large\rm \frac{27x^6}{9x^2}$

55. pooja195

$\huge~\frac{ 3\times3\times3~\times~x~\times~x~\times~x~\times~x~\times~x~\times~x }{ 3\times3~\times~x~\times~x}$

56. pooja195

AW MAN it got cut >:(

57. zepdrix

@pooja195 woops i almost did @ the wrong name. apparently there's a poop42 online.

58. pooja195
59. zepdrix

|dw:1434054597549:dw|

60. zepdrix

Since m is the midpoint, then these segments are equal.|dw:1434054703228:dw|

61. zepdrix

And they told us that these segments have length,|dw:1434054731934:dw|

62. zepdrix

If the line segments are equal, hmm what can we do poojam? :d

63. pooja195

poojam 0)0 23x+5=25x-4 right?

64. zepdrix

mmm good, yes. they'r equal, so we can set them equal to one another. then solve for x :)

65. pooja195

x=9/2

66. zepdrix

yay good job \c:/

67. pooja195

is that it?

68. pooja195

o.O

69. zepdrix

oh my bad, no i guess it's not XD lol

70. pooja195

o-o

71. zepdrix

that gives us the value of x. Now we use x to find the length of PQ

72. pooja195

so we plug the X value into the equation ? o.O

73. zepdrix

well, we want to use a slightly different formula this time. we don't want two equal pieces. this time we want the ENTIRE length PQ. how do we set that up? :d

74. pooja195

im not sure :/

75. zepdrix

|dw:1434055116885:dw|The distance PQ is going to be this first piece PLUS this other piece, ya?

76. pooja195

yea

77. pooja195

78. zepdrix

ya we'll add to find total length: $$\Large\rm 23x+5+25x-4$$ and you can plug in your value at this point.

79. pooja195

217

80. zepdrix

hmm

81. pooja195

:/

82. zepdrix

We plug in our stuff,$\Large\rm 23\left(\frac{9}{2}\right)+5+25\left(\frac{9}{2}\right)-4$Let's combine the non-fractional parts first, 5 and -4 give us 1.$\Large\rm 23\left(\frac{9}{2}\right)+25\left(\frac{9}{2}\right)+1$Now the fractional part, how many of these 9/2's do we have? Ummm looks like 48 of them.$\Large\rm 48\left(\frac{9}{2}\right)+1$Divide by 2 gives,$\Large\rm 24\cdot9+1$Which equals 217, oo good job! :)

83. zepdrix

I did my math wrong the first time hehe

84. pooja195

LOL >:(

85. pooja195

thnks zeppy :)