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zepdrix

  • one year ago

Better put your Poojamas on! It's Study Time!!!

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  1. zepdrix
    • one year ago
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    |dw:1433131922743:dw| @pooja195

  2. pooja195
    • one year ago
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    LOL

  3. zepdrix
    • one year ago
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    So what's going on now? Factoring?

  4. zepdrix
    • one year ago
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    Or other stuff?

  5. pooja195
    • one year ago
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    its the same fraction stuff

  6. zepdrix
    • one year ago
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    fraction stuff? like this?\[\Large\rm \frac{x}{x+1}=\frac{-4}{x}\]solve for x? :O

  7. pooja195
    • one year ago
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    x*x=x^2 -4(x+1)=-4x-4 x^2=-4x-4 add to put everything on the same side as the x^2 x^2+4x+4=0 (x+2)(x+2) x=-2

  8. zepdrix
    • one year ago
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    yay good job \c:/

  9. zepdrix
    • one year ago
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    so that one was cake? what are we having trouble with then? <.< hmm

  10. pooja195
    • one year ago
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    just need some practice :P

  11. pooja195
    • one year ago
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    to figure out what I don't get :P so u can explain ofc

  12. zepdrix
    • one year ago
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    oh oh oh i remember.

  13. zepdrix
    • one year ago
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    \[\Large\rm \frac{16x^2}{21x+7}\div\frac{4x^2-4x}{7x-7}\]This one is kinda tough :o lemme know where you get stuck.

  14. zepdrix
    • one year ago
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    @pooja195 do you think you can finish this last one? :)

  15. pooja195
    • one year ago
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    Ok :/ \[\huge~1)~~\frac{ 16x^2 }{ 21x+7}\times \frac{ 7x-7 }{ 4x^2-4x }\] \[\huge~2)~\frac{ 16x^2 }{ 7(3x+1) }\times \frac{ 7(x-1) }{ 4x(x-1) }\]

  16. pooja195
    • one year ago
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    @zepdrix :)

  17. zepdrix
    • one year ago
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    Ok good, now cancel stuff out if you can :)

  18. zepdrix
    • one year ago
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    Wow that is some big font +_+ lol

  19. pooja195
    • one year ago
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    Me like BIG > :) \[\huge~\frac{ 16x^2 }{ 7(3x+1) }\times \frac{ 7 }{ 4x }=\frac{ ;-; }{ ;-; }\]

  20. zepdrix
    • one year ago
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    lol, cancel moar

  21. zepdrix
    • one year ago
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    lots moar

  22. pooja195
    • one year ago
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    You cant cancel anymore! :/

  23. pooja195
    • one year ago
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    \[\huge~\frac{ 16x^2 }{ (3x+1) }\times \frac{ }{ 4x }=\frac{ ;-; }{ ;-; }\]

  24. pooja195
    • one year ago
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    :/

  25. zepdrix
    • one year ago
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    what happens when you divide the 7's out? What are you left with up there? Hint: It's not a zero. Dividing doesn't give you 0.

  26. pooja195
    • one year ago
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    1

  27. zepdrix
    • one year ago
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    \[\Large\rm =\frac{16x^2}{3x+1}\cdot\frac{1}{4x}\]Mmm k sounds right so far. MOAR

  28. pooja195
    • one year ago
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    Theres no more!

  29. zepdrix
    • one year ago
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    16 has a 4 in it. x^2 has an x in it.

  30. zepdrix
    • one year ago
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    There is moar.

  31. pooja195
    • one year ago
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    \[\Huge~\frac{ (x+4)(x-4) }{ 3x+1 }\times \frac{ 1 }{ 4x }\] NO MORE.

  32. pooja195
    • one year ago
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    see

  33. zepdrix
    • one year ago
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    woah what in the world..?

  34. zepdrix
    • one year ago
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    break down the 16. 16 = ? x ?

  35. pooja195
    • one year ago
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    4x^2 ?

  36. pooja195
    • one year ago
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    wait no

  37. pooja195
    • one year ago
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    4x

  38. zepdrix
    • one year ago
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    what..? 16 = what times what

  39. pooja195
    • one year ago
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    4 times 4

  40. zepdrix
    • one year ago
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    \[\Large\rm =\frac{16x^2}{3x+1}\cdot\frac{1}{4x}\quad=\quad\frac{4\cdot4x^2}{3x+1}\cdot\frac{1}{4x}\]Good :o and x^2 is x times x, ya?

  41. pooja195
    • one year ago
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    O_o

  42. zepdrix
    • one year ago
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    \[\Large\rm =\frac{4\cdot4\cdot x\cdot x }{3x+1}\cdot\frac{1}{4x}\]

  43. pooja195
    • one year ago
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    Oh ok that makes sense ....

  44. pooja195
    • one year ago
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    I cant cancel more :/

  45. pooja195
    • one year ago
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    im consfused .-.

  46. zepdrix
    • one year ago
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    \[\Large\rm =\frac{\color{red}{4}\cdot4\cdot x\cdot x }{3x+1}\cdot\frac{1}{\color{red}{4}x}\]MOOAEERRRRR

  47. zepdrix
    • one year ago
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    \[\Large\rm =\frac{\color{red}{4}\cdot4\cdot x\cdot \color{royalblue}{x} }{3x+1}\cdot\frac{1}{\color{red}{4}\color{royalblue}{x}}\]MOER MOAR MOARRRR

  48. pooja195
    • one year ago
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    \[\huge~\frac{ 4x }{ 3x+1}~\]

  49. pooja195
    • one year ago
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    WAIT DONT SAY IT

  50. pooja195
    • one year ago
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    Thats answer is 1??????????????????

  51. zepdrix
    • one year ago
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    4x/(3x+1) ? ooo good job \c:/

  52. pooja195
    • one year ago
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    -_- smh

  53. zepdrix
    • one year ago
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    You're having a lot of trouble breaking these things down, we have to do more :(

  54. zepdrix
    • one year ago
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    Simplify:\[\Large\rm \frac{27x^6}{9x^2}\]

  55. pooja195
    • one year ago
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    \[\huge~\frac{ 3\times3\times3~\times~x~\times~x~\times~x~\times~x~\times~x~\times~x }{ 3\times3~\times~x~\times~x}\]

  56. pooja195
    • one year ago
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    AW MAN it got cut >:(

  57. zepdrix
    • one year ago
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    @pooja195 woops i almost did @ the wrong name. apparently there's a poop42 online.

  58. pooja195
    • one year ago
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    ._. http://prntscr.com/7fvldy

  59. zepdrix
    • one year ago
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    |dw:1434054597549:dw|

  60. zepdrix
    • one year ago
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    Since m is the midpoint, then these segments are `equal`.|dw:1434054703228:dw|

  61. zepdrix
    • one year ago
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    And they told us that these segments have length,|dw:1434054731934:dw|

  62. zepdrix
    • one year ago
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    If the line segments are `equal`, hmm what can we do poojam? :d

  63. pooja195
    • one year ago
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    poojam 0)0 23x+5=25x-4 right?

  64. zepdrix
    • one year ago
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    mmm good, yes. they'r equal, so we can set them equal to one another. then solve for x :)

  65. pooja195
    • one year ago
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    x=9/2

  66. zepdrix
    • one year ago
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    yay good job \c:/

  67. pooja195
    • one year ago
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    is that it?

  68. pooja195
    • one year ago
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    o.O

  69. zepdrix
    • one year ago
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    oh my bad, no i guess it's not XD lol

  70. pooja195
    • one year ago
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    o-o

  71. zepdrix
    • one year ago
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    that gives us the value of x. Now we use x to find the length of PQ

  72. pooja195
    • one year ago
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    so we plug the X value into the equation ? o.O

  73. zepdrix
    • one year ago
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    well, we want to use a slightly different formula this time. we don't want two equal pieces. this time we want the ENTIRE length PQ. how do we set that up? :d

  74. pooja195
    • one year ago
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    im not sure :/

  75. zepdrix
    • one year ago
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    |dw:1434055116885:dw|The distance PQ is going to be this first piece PLUS this other piece, ya?

  76. pooja195
    • one year ago
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    yea

  77. pooja195
    • one year ago
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    so we add?

  78. zepdrix
    • one year ago
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    ya we'll add to find total length: \(\Large\rm 23x+5+25x-4\) and you can plug in your value at this point.

  79. pooja195
    • one year ago
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    217

  80. zepdrix
    • one year ago
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    hmm

  81. pooja195
    • one year ago
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    :/

  82. zepdrix
    • one year ago
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    We plug in our stuff,\[\Large\rm 23\left(\frac{9}{2}\right)+5+25\left(\frac{9}{2}\right)-4\]Let's combine the non-fractional parts first, 5 and -4 give us 1.\[\Large\rm 23\left(\frac{9}{2}\right)+25\left(\frac{9}{2}\right)+1\]Now the fractional part, how many of these 9/2's do we have? Ummm looks like 48 of them.\[\Large\rm 48\left(\frac{9}{2}\right)+1\]Divide by 2 gives,\[\Large\rm 24\cdot9+1\]Which equals 217, oo good job! :)

  83. zepdrix
    • one year ago
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    I did my math wrong the first time hehe

  84. pooja195
    • one year ago
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    LOL >:(

  85. pooja195
    • one year ago
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    thnks zeppy :)

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