zepdrix
  • zepdrix
Better put your Poojamas on! It's Study Time!!!
Chemistry
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

zepdrix
  • zepdrix
|dw:1433131922743:dw| @pooja195
pooja195
  • pooja195
LOL
zepdrix
  • zepdrix
So what's going on now? Factoring?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zepdrix
  • zepdrix
Or other stuff?
pooja195
  • pooja195
its the same fraction stuff
zepdrix
  • zepdrix
fraction stuff? like this?\[\Large\rm \frac{x}{x+1}=\frac{-4}{x}\]solve for x? :O
pooja195
  • pooja195
x*x=x^2 -4(x+1)=-4x-4 x^2=-4x-4 add to put everything on the same side as the x^2 x^2+4x+4=0 (x+2)(x+2) x=-2
zepdrix
  • zepdrix
yay good job \c:/
zepdrix
  • zepdrix
so that one was cake? what are we having trouble with then? <.< hmm
pooja195
  • pooja195
just need some practice :P
pooja195
  • pooja195
to figure out what I don't get :P so u can explain ofc
zepdrix
  • zepdrix
oh oh oh i remember.
zepdrix
  • zepdrix
\[\Large\rm \frac{16x^2}{21x+7}\div\frac{4x^2-4x}{7x-7}\]This one is kinda tough :o lemme know where you get stuck.
zepdrix
  • zepdrix
@pooja195 do you think you can finish this last one? :)
pooja195
  • pooja195
Ok :/ \[\huge~1)~~\frac{ 16x^2 }{ 21x+7}\times \frac{ 7x-7 }{ 4x^2-4x }\] \[\huge~2)~\frac{ 16x^2 }{ 7(3x+1) }\times \frac{ 7(x-1) }{ 4x(x-1) }\]
pooja195
  • pooja195
zepdrix
  • zepdrix
Ok good, now cancel stuff out if you can :)
zepdrix
  • zepdrix
Wow that is some big font +_+ lol
pooja195
  • pooja195
Me like BIG > :) \[\huge~\frac{ 16x^2 }{ 7(3x+1) }\times \frac{ 7 }{ 4x }=\frac{ ;-; }{ ;-; }\]
zepdrix
  • zepdrix
lol, cancel moar
zepdrix
  • zepdrix
lots moar
pooja195
  • pooja195
You cant cancel anymore! :/
pooja195
  • pooja195
\[\huge~\frac{ 16x^2 }{ (3x+1) }\times \frac{ }{ 4x }=\frac{ ;-; }{ ;-; }\]
pooja195
  • pooja195
:/
zepdrix
  • zepdrix
what happens when you divide the 7's out? What are you left with up there? Hint: It's not a zero. Dividing doesn't give you 0.
pooja195
  • pooja195
1
zepdrix
  • zepdrix
\[\Large\rm =\frac{16x^2}{3x+1}\cdot\frac{1}{4x}\]Mmm k sounds right so far. MOAR
pooja195
  • pooja195
Theres no more!
zepdrix
  • zepdrix
16 has a 4 in it. x^2 has an x in it.
zepdrix
  • zepdrix
There is moar.
pooja195
  • pooja195
\[\Huge~\frac{ (x+4)(x-4) }{ 3x+1 }\times \frac{ 1 }{ 4x }\] NO MORE.
pooja195
  • pooja195
see
zepdrix
  • zepdrix
woah what in the world..?
zepdrix
  • zepdrix
break down the 16. 16 = ? x ?
pooja195
  • pooja195
4x^2 ?
pooja195
  • pooja195
wait no
pooja195
  • pooja195
4x
zepdrix
  • zepdrix
what..? 16 = what times what
pooja195
  • pooja195
4 times 4
zepdrix
  • zepdrix
\[\Large\rm =\frac{16x^2}{3x+1}\cdot\frac{1}{4x}\quad=\quad\frac{4\cdot4x^2}{3x+1}\cdot\frac{1}{4x}\]Good :o and x^2 is x times x, ya?
pooja195
  • pooja195
O_o
zepdrix
  • zepdrix
\[\Large\rm =\frac{4\cdot4\cdot x\cdot x }{3x+1}\cdot\frac{1}{4x}\]
pooja195
  • pooja195
Oh ok that makes sense ....
pooja195
  • pooja195
I cant cancel more :/
pooja195
  • pooja195
im consfused .-.
zepdrix
  • zepdrix
\[\Large\rm =\frac{\color{red}{4}\cdot4\cdot x\cdot x }{3x+1}\cdot\frac{1}{\color{red}{4}x}\]MOOAEERRRRR
zepdrix
  • zepdrix
\[\Large\rm =\frac{\color{red}{4}\cdot4\cdot x\cdot \color{royalblue}{x} }{3x+1}\cdot\frac{1}{\color{red}{4}\color{royalblue}{x}}\]MOER MOAR MOARRRR
pooja195
  • pooja195
\[\huge~\frac{ 4x }{ 3x+1}~\]
pooja195
  • pooja195
WAIT DONT SAY IT
pooja195
  • pooja195
Thats answer is 1??????????????????
zepdrix
  • zepdrix
4x/(3x+1) ? ooo good job \c:/
pooja195
  • pooja195
-_- smh
zepdrix
  • zepdrix
You're having a lot of trouble breaking these things down, we have to do more :(
zepdrix
  • zepdrix
Simplify:\[\Large\rm \frac{27x^6}{9x^2}\]
pooja195
  • pooja195
\[\huge~\frac{ 3\times3\times3~\times~x~\times~x~\times~x~\times~x~\times~x~\times~x }{ 3\times3~\times~x~\times~x}\]
pooja195
  • pooja195
AW MAN it got cut >:(
zepdrix
  • zepdrix
@pooja195 woops i almost did @ the wrong name. apparently there's a poop42 online.
pooja195
  • pooja195
._. http://prntscr.com/7fvldy
zepdrix
  • zepdrix
|dw:1434054597549:dw|
zepdrix
  • zepdrix
Since m is the midpoint, then these segments are `equal`.|dw:1434054703228:dw|
zepdrix
  • zepdrix
And they told us that these segments have length,|dw:1434054731934:dw|
zepdrix
  • zepdrix
If the line segments are `equal`, hmm what can we do poojam? :d
pooja195
  • pooja195
poojam 0)0 23x+5=25x-4 right?
zepdrix
  • zepdrix
mmm good, yes. they'r equal, so we can set them equal to one another. then solve for x :)
pooja195
  • pooja195
x=9/2
zepdrix
  • zepdrix
yay good job \c:/
pooja195
  • pooja195
is that it?
pooja195
  • pooja195
o.O
zepdrix
  • zepdrix
oh my bad, no i guess it's not XD lol
pooja195
  • pooja195
o-o
zepdrix
  • zepdrix
that gives us the value of x. Now we use x to find the length of PQ
pooja195
  • pooja195
so we plug the X value into the equation ? o.O
zepdrix
  • zepdrix
well, we want to use a slightly different formula this time. we don't want two equal pieces. this time we want the ENTIRE length PQ. how do we set that up? :d
pooja195
  • pooja195
im not sure :/
zepdrix
  • zepdrix
|dw:1434055116885:dw|The distance PQ is going to be this first piece PLUS this other piece, ya?
pooja195
  • pooja195
yea
pooja195
  • pooja195
so we add?
zepdrix
  • zepdrix
ya we'll add to find total length: \(\Large\rm 23x+5+25x-4\) and you can plug in your value at this point.
pooja195
  • pooja195
217
zepdrix
  • zepdrix
hmm
pooja195
  • pooja195
:/
zepdrix
  • zepdrix
We plug in our stuff,\[\Large\rm 23\left(\frac{9}{2}\right)+5+25\left(\frac{9}{2}\right)-4\]Let's combine the non-fractional parts first, 5 and -4 give us 1.\[\Large\rm 23\left(\frac{9}{2}\right)+25\left(\frac{9}{2}\right)+1\]Now the fractional part, how many of these 9/2's do we have? Ummm looks like 48 of them.\[\Large\rm 48\left(\frac{9}{2}\right)+1\]Divide by 2 gives,\[\Large\rm 24\cdot9+1\]Which equals 217, oo good job! :)
zepdrix
  • zepdrix
I did my math wrong the first time hehe
pooja195
  • pooja195
LOL >:(
pooja195
  • pooja195
thnks zeppy :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.