- ccchristian1

Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $30 to buy a total of 22 packets of wafers of the two varieties.

- schrodinger

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- ccchristian1

Part A: Write a system of equations that can be solved to find the number of packets of strawberry wafers and the number of packets of chocolate wafers that Devon and his friends bought at the carnival. Define the variables used in the equations. (5 points)
Part B: How many packets of chocolate wafers and strawberry wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer. (5 points)

- ccchristian1

- anonymous

hello

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- ccchristian1

yeah?

- anonymous

lets make strawberry x and chocolate y

- UsukiDoll

oh gawd I hate these word problems sorry ^^'

- ccchristian1

@UsukiDoll you got time ? lol

- ccchristian1

oh alright its okay lol @UsukiDoll

- anonymous

strawberry is 3 dollars so 3x
chocolate is 1 dollar so 1y

- anonymous

3x+y=30

- anonymous

That's the first equation

- ccchristian1

thats for part a?^

- anonymous

the second equation is
x+y=22

- anonymous

both equations are part of the 'system of equations'

- anonymous

For part B we need to solve for x and y.

- anonymous

are you familiar with substitution?

- ccchristian1

not really

- anonymous

ok, so we have our two equations
3x+y=30 and
x+y=22

- anonymous

isolate x or y in one of the equations and then plug it into the other equation

- anonymous

so isolate x in the second equation
x+y=22

- ccchristian1

3x+y=22?

- anonymous

nope, we're just looking at x+y=22 right now

- anonymous

so get x by itself

- ccchristian1

so what will it be?

- anonymous

we have to subtract y from both sides

- anonymous

this gives x=22-y

- anonymous

now we take 22-y and replace that with x in the other equation

- anonymous

3(22-y)+y=30

- anonymous

solve for y

- ccchristian1

this will tell us how much packets did they buy

- anonymous

ya

- ccchristian1

then whats next ?

- ccchristian1

after that

- anonymous

y will tell us how many chocolate was bought.
what did you get for y

- ccchristian1

33?

- anonymous

nope, you have to solve the equation

- anonymous

first foil out 3(22-y)

- ccchristian1

19?

- anonymous

where are you getting these numbers?

- ccchristian1

18?

- anonymous

that's right, good job

- ccchristian1

yeeeeeeee les get it

- anonymous

so we know there are 18 chocolate wafers. how many strawberry are there?

- anonymous

substitute it back into this equation
x+y=22

- ccchristian1

to what number ??

- anonymous

well we just found that y was 18

- ccchristian1

soooo......

- ccchristian1

so 22?

- anonymous

x+y=22
If y is 18, what is x

- ccchristian1

22?

- anonymous

x+(18)=22

- anonymous

solve for x

- ccchristian1

4?

- anonymous

correct
so there are 4 strawberry and 18 chocolate

- anonymous

4 x 3 + 18 x 1 = 30
18 + 4 = 22

- anonymous

This method is called the substitution method where you substitute one equation in for another

Looking for something else?

Not the answer you are looking for? Search for more explanations.