cutiecomittee123
  • cutiecomittee123
how do find the vertex and foci of this hyperbola (x-2)^2/36 - (y+1)^2/64 =1
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
you can simply guess the vertex of the hyperbola has (2,-1) the focii is (+ae,0) , (-ae,0) you can find e by b^2 = a^2(e^2-1) and just shift the vertex wrt the vertex
cutiecomittee123
  • cutiecomittee123
Okay let me try that and see what I get
anonymous
  • anonymous
sure :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

cutiecomittee123
  • cutiecomittee123
wait so I plugged into my calculator "8=6(e^2-1) I got 16.3096
cutiecomittee123
  • cutiecomittee123
I feel like I did something wrong
anonymous
  • anonymous
dear a^2 =36 and b^2 = 64 you plugged a and b instead of a^2 and b^2
cutiecomittee123
  • cutiecomittee123
oh wow thanks
cutiecomittee123
  • cutiecomittee123
let me redo that using a^2 and b^2
cutiecomittee123
  • cutiecomittee123
now I get 97

Looking for something else?

Not the answer you are looking for? Search for more explanations.