Will MEDAL Cos(sin2/3 + tan3/2) Sum and Difference Formula Can someone do this problem and tell me what they get so I can compare it with my own

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Will MEDAL Cos(sin2/3 + tan3/2) Sum and Difference Formula Can someone do this problem and tell me what they get so I can compare it with my own

Mathematics
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so.. we're dealing with \[\cos(\theta+ \beta) \] where \[\theta = \sin \frac{2}{3}, \beta = \tan \frac{3}{2}\] ?
\[\cos( \theta+ \beta) = \cos(\theta)\cos(\beta)-\sin(\theta)\sin(\beta)\]
|dw:1433138555024:dw|

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Other answers:

if my beta is tangent then I have to find cosine and sine of my beta|dw:1433138769787:dw|
\[\sin(\beta) = \frac{3}{\sqrt{13}}, \cos(\beta) = \frac{2}{\sqrt{13}}\]
\[\cos( \theta+ \beta) = \cos(\theta)\cos(\beta)-\sin(\theta)\sin(\beta)\] \[\sin(\beta) = \frac{3}{\sqrt{13}}, \cos(\beta) = \frac{2}{\sqrt{13}} \] \[\sin(\theta) = \frac{2}{3}, \cos (\theta) = \frac{\sqrt{5}}{3}\]
\[\cos( \theta+ \beta) =((\frac{2}{\sqrt{13}})-\frac{2}{3}(\frac{3}{\sqrt{13}})\] code broke |dw:1433139398171:dw|
That's what I got, thanks so much
=) whew.. that was a nerve wrecking one due to the way it was written so I had to reread a part of my notes and see what was going on ^^

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