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anonymous

  • one year ago

Line NA is congruent to line PA, MO is perpendicular to NA, RO is perpendicular to PA, and MO=6 feet. and this is the shape http://assets.openstudy.com/updates/attachments/4fd03b3fe4b0e0466317e3ef-mskyeg-1339046737323-cusersmsgpicturesmc0064.jpg

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  1. anonymous
    • one year ago
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    hey guys i rely need help on this. i'm out of options. please help

  2. anonymous
    • one year ago
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    Hmmm....This is hard

  3. anonymous
    • one year ago
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    No clue

  4. anonymous
    • one year ago
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    darn

  5. anonymous
    • one year ago
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    @igreen @paki

  6. anonymous
    • one year ago
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    What are you asked to solve for?

  7. anonymous
    • one year ago
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    po

  8. anonymous
    • one year ago
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    i don't think i can give you any solid geometric reasoning here... but I'm pretty sure PO = 3 you're given this.. |dw:1433140089676:dw|

  9. anonymous
    • one year ago
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    because A is the center of the circle, and AN is perpendicular to MO, it must bisect MO. therefore MN = NO |dw:1433140254126:dw|

  10. anonymous
    • one year ago
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    you also know that AP and AN are equal lengths: |dw:1433140308669:dw|

  11. anonymous
    • one year ago
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    oh my god thank you so much

  12. anonymous
    • one year ago
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    For the lines RO and MO to intersect at a point on the edge of the circle, and for both of the lines to be perpendicular to AP and AN respectively, OR has to be a reflection of MO |dw:1433140389665:dw|

  13. anonymous
    • one year ago
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    so you end up with: |dw:1433140431775:dw|

  14. nikato
    • one year ago
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    http://www.regentsprep.org/regents/math/geometry/gp14/circlechords.htm extending NA such that it is a radius since NA is perpendicular to chord MO, it is a perpendicular bisector. so NO= half of 6 which is 3

  15. nikato
    • one year ago
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    then using HL theorem, prove triangle APO= ANO and PO= NP by CPCTC

  16. anonymous
    • one year ago
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    There's the solid geometry I was missing :) Cheers @nikato

  17. anonymous
    • one year ago
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    PO = NO* ?

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