anonymous
  • anonymous
Line NA is congruent to line PA, MO is perpendicular to NA, RO is perpendicular to PA, and MO=6 feet. and this is the shape http://assets.openstudy.com/updates/attachments/4fd03b3fe4b0e0466317e3ef-mskyeg-1339046737323-cusersmsgpicturesmc0064.jpg
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
hey guys i rely need help on this. i'm out of options. please help
anonymous
  • anonymous
Hmmm....This is hard
anonymous
  • anonymous
No clue

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anonymous
  • anonymous
darn
anonymous
  • anonymous
@igreen @paki
anonymous
  • anonymous
What are you asked to solve for?
anonymous
  • anonymous
po
anonymous
  • anonymous
i don't think i can give you any solid geometric reasoning here... but I'm pretty sure PO = 3 you're given this.. |dw:1433140089676:dw|
anonymous
  • anonymous
because A is the center of the circle, and AN is perpendicular to MO, it must bisect MO. therefore MN = NO |dw:1433140254126:dw|
anonymous
  • anonymous
you also know that AP and AN are equal lengths: |dw:1433140308669:dw|
anonymous
  • anonymous
oh my god thank you so much
anonymous
  • anonymous
For the lines RO and MO to intersect at a point on the edge of the circle, and for both of the lines to be perpendicular to AP and AN respectively, OR has to be a reflection of MO |dw:1433140389665:dw|
anonymous
  • anonymous
so you end up with: |dw:1433140431775:dw|
nikato
  • nikato
http://www.regentsprep.org/regents/math/geometry/gp14/circlechords.htm extending NA such that it is a radius since NA is perpendicular to chord MO, it is a perpendicular bisector. so NO= half of 6 which is 3
nikato
  • nikato
then using HL theorem, prove triangle APO= ANO and PO= NP by CPCTC
anonymous
  • anonymous
There's the solid geometry I was missing :) Cheers @nikato
anonymous
  • anonymous
PO = NO* ?

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