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ashleynguyenx3
 one year ago
Best ResponseYou've already chosen the best response.0\[(3^6)^2\] Multiply the numbers 6x2

ashleynguyenx3
 one year ago
Best ResponseYou've already chosen the best response.0When theres exponentials and the numbers are multiplying, add.

ashleynguyenx3
 one year ago
Best ResponseYou've already chosen the best response.0so 3^12 x 3^0 (Just add the exponents)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1you guys forgot to mention that whenever the exponent is 0 the ending result is a 1? \[3^0 = 1\] and as for \[(3^6)^2\] you can either multiply the 2 with the 6 making it \[6 \times 2 = 12\] or you can write \[(3^6)\] two times. the outer exponent tells you how many times to write and using exponential laws like \[a^3a^3 \rightarrow a^{3+3} \rightarrow a^6\] so in this case for \[(3^6)(3^6) \rightarrow 3^{6+6} \rightarrow 3^{12}\] \[3^{12} \cdot 3^0\] Since \[3^0 = 1\] \[3^{12} \cdot 1 \rightarrow 3^{12} \]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1\[(3^6)^2\cdot3^0=3^{6\times2+0}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1that's still 3^12 regardless of what you're doing... as long as none of the math laws are being broken, more than one method to solving this problem exists. This issue lead to a lot of debate between me and my Mathematical Biology professor last semester.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1and again there's the zero exponent special case... why not use that first and then use exponential laws on ((3^6))^2

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1biologist will tell you that multiplication and division are that same thing

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1boooooooooo! Taking the special zero exponent case would've been easier.
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