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anonymous

  • one year ago

http://prntscr.com/7brctg EASY QUESTION. QUICK MEDAL.

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  1. anonymous
    • one year ago
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    531438 i think.

  2. ashleynguyenx3
    • one year ago
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    \[(3^6)^2\] Multiply the numbers 6x2

  3. ashleynguyenx3
    • one year ago
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    When theres exponentials and the numbers are multiplying, add.

  4. ashleynguyenx3
    • one year ago
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    so 3^12 x 3^0 (Just add the exponents)

  5. UsukiDoll
    • one year ago
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    you guys forgot to mention that whenever the exponent is 0 the ending result is a 1? \[3^0 = 1\] and as for \[(3^6)^2\] you can either multiply the 2 with the 6 making it \[6 \times 2 = 12\] or you can write \[(3^6)\] two times. the outer exponent tells you how many times to write and using exponential laws like \[a^3a^3 \rightarrow a^{3+3} \rightarrow a^6\] so in this case for \[(3^6)(3^6) \rightarrow 3^{6+6} \rightarrow 3^{12}\] \[3^{12} \cdot 3^0\] Since \[3^0 = 1\] \[3^{12} \cdot 1 \rightarrow 3^{12} \]

  6. UnkleRhaukus
    • one year ago
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    \[(3^6)^2\cdot3^0=3^{6\times2+0}\]

  7. UsukiDoll
    • one year ago
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    that's still 3^12 regardless of what you're doing... as long as none of the math laws are being broken, more than one method to solving this problem exists. This issue lead to a lot of debate between me and my Mathematical Biology professor last semester.

  8. UsukiDoll
    • one year ago
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    and again there's the zero exponent special case... why not use that first and then use exponential laws on ((3^6))^2

  9. UsukiDoll
    • one year ago
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    yay medal :)

  10. UnkleRhaukus
    • one year ago
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    biologist will tell you that multiplication and division are that same thing

  11. UsukiDoll
    • one year ago
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    D:

  12. UsukiDoll
    • one year ago
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    boooooooooo! Taking the special zero exponent case would've been easier.

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