## anonymous one year ago http://prntscr.com/7brctg EASY QUESTION. QUICK MEDAL.

1. anonymous

531438 i think.

2. ashleynguyenx3

$(3^6)^2$ Multiply the numbers 6x2

3. ashleynguyenx3

When theres exponentials and the numbers are multiplying, add.

4. ashleynguyenx3

so 3^12 x 3^0 (Just add the exponents)

5. UsukiDoll

you guys forgot to mention that whenever the exponent is 0 the ending result is a 1? $3^0 = 1$ and as for $(3^6)^2$ you can either multiply the 2 with the 6 making it $6 \times 2 = 12$ or you can write $(3^6)$ two times. the outer exponent tells you how many times to write and using exponential laws like $a^3a^3 \rightarrow a^{3+3} \rightarrow a^6$ so in this case for $(3^6)(3^6) \rightarrow 3^{6+6} \rightarrow 3^{12}$ $3^{12} \cdot 3^0$ Since $3^0 = 1$ $3^{12} \cdot 1 \rightarrow 3^{12}$

6. UnkleRhaukus

$(3^6)^2\cdot3^0=3^{6\times2+0}$

7. UsukiDoll

that's still 3^12 regardless of what you're doing... as long as none of the math laws are being broken, more than one method to solving this problem exists. This issue lead to a lot of debate between me and my Mathematical Biology professor last semester.

8. UsukiDoll

and again there's the zero exponent special case... why not use that first and then use exponential laws on ((3^6))^2

9. UsukiDoll

yay medal :)

10. UnkleRhaukus

biologist will tell you that multiplication and division are that same thing

11. UsukiDoll

D:

12. UsukiDoll

boooooooooo! Taking the special zero exponent case would've been easier.