At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

with respect to x?

Yep!

I guess it would be chain rule on both sides but it gets a bit messy when I do it

I just corrected the question, the right side is to the power of 2

Implicitly differentiate the terms with \(y\), like this:
\[\frac{d}{dx}(y^2) = 2y\frac{dy}{dx}\]

oh ok,
what do you get for the left hand side?

I got 2x + 2yy'

good

now the righthand side
\[=\frac d{dx}(2x^2+2y^2-x)^2\]

Would it be
2(2x^2 + 2y^2 -x)(4x +4yy' -1) ?

looks good!

Now the simplification XD

hmmm, i don't think it simplifies very far,
implicit derivatives often don't simplify nice

What do you get?

please look @ my question after this @UnkleRhaukus

This is what I get at the end ...
\[\frac{ 2(4x^3 - 3x^2 +4xy^2 - y^2) }{ y(1-8x^2 - 8y^2 +4x )}\]

@UnkleRhaukus is this what you get as well?

what happened to the equals sign?

What I'm trying to solve is actually this question...

Oh lol forgot that... y' = to all that ^

Ooo I think the same derivative :)
I think you did that correctly

Gave yourself a little extra work maybe though.. hmm

I got the same derivative* woops typo

Oh that's a relief! Haha at least i got that right XD

Well I only solved for y'

Alright so I'm gonna give that a try and tell you what I get :)

Please don't leave! :D

fine fine fine -_-

Lol so plugging in the x and y values I got -1... Tell me I'm not wrong :D

Let's look at the graph to sort of check our work easily.

|dw:1433147166496:dw|Here is the point (0,1/2)

Does the slope look like a -1?
Hmmm not so much :[

Maybe its positive? haha

I don't know where i went wrong >.<

Oh wait no I was right!! Just went a little kookoo at the end! I get -.5/-.5 and that's 1 not -1 XD

positive 1? Ooo that seems to match the picture a lot better also! :) yay

Haha awesome! XD

why -x? :o

Oh that was me going loco again :D haha sorry its
y = x + 1/2

Look at this!!!
Thanks soooo soo much!!
I have a calculus midterm tomorrow, you have no idea how much I appreciate your help!!

yay team \c:/
np

Hahaha YaY :D