hockeychick23
  • hockeychick23
Using the tree diagram, you just constructed and make a table showing the probability distribution of getting zero, one, or both questions right by guessing. (i attached the tree diagram)
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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hockeychick23
  • hockeychick23
1 Attachment
hockeychick23
  • hockeychick23
@welshfella @kropot72
hockeychick23
  • hockeychick23
I got: Probability of getting zero questions right by guessing: .5626(.75)= .42195 Probability of getting one question right by guessing: (0.75)(.1875)= .140625 (0.25)(.0625)= 0.015625 .140625+0.015625= .15625 but I'm not sure if i did it correctly, can someone check my answer please?

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UnkleRhaukus
  • UnkleRhaukus
don't multiply
UnkleRhaukus
  • UnkleRhaukus
the number on the right most nodes are the total probabilities already
hockeychick23
  • hockeychick23
oh ok so the probability of getting zero right is .5625, getting one right is .25+.1875=.4375 and getting both right would be .1875?
UnkleRhaukus
  • UnkleRhaukus
|dw:1433151671567:dw|
UnkleRhaukus
  • UnkleRhaukus
yes the probability of getting zero right is .5625,
UnkleRhaukus
  • UnkleRhaukus
the probability of getting 1 right is the sum of the two probability of the nodes in the tree that are exactly 1 right ansewer
hockeychick23
  • hockeychick23
yea i got .25+.1875=.4375
UnkleRhaukus
  • UnkleRhaukus
ie P(1) = P(wr) + P(rw)
UnkleRhaukus
  • UnkleRhaukus
0.25 is the probability that the first question is right, but we want to add the probabilities that exactly one question is right
hockeychick23
  • hockeychick23
oh sorry so its .1875+.0625= .25
UnkleRhaukus
  • UnkleRhaukus
nope
UnkleRhaukus
  • UnkleRhaukus
|dw:1433152150638:dw|add these
hockeychick23
  • hockeychick23
.375
UnkleRhaukus
  • UnkleRhaukus
yes
hockeychick23
  • hockeychick23
and then both right would be .1875
UnkleRhaukus
  • UnkleRhaukus
**error in diagram |dw:1433152335528:dw|
UnkleRhaukus
  • UnkleRhaukus
there is only one leaf on the tree that has both right answers P(rr) =
hockeychick23
  • hockeychick23
yea that leaf says .0625
UnkleRhaukus
  • UnkleRhaukus
|dw:1433152413453:dw|
UnkleRhaukus
  • UnkleRhaukus
yes,
hockeychick23
  • hockeychick23
i think i drew my diagram wrong when i constructed it
UnkleRhaukus
  • UnkleRhaukus
why do you say that? it seems right to me its multiple choice (four options) two questions
hockeychick23
  • hockeychick23
oh i just flip flopped the wrong and right on the second leaf
UnkleRhaukus
  • UnkleRhaukus
ah yeah
UnkleRhaukus
  • UnkleRhaukus
if we add up all the probabilities P(0) = 0.5625 P(1) = 0.1875+0.1875 = 0.3750 P(2) = 0.0625 P(0)+P(1)+P(2) = 1
hockeychick23
  • hockeychick23
oh awesome! so if i made it into a table like it was asking could i just draw it like this:
1 Attachment
UnkleRhaukus
  • UnkleRhaukus
wcheck that last entry in the table again
hockeychick23
  • hockeychick23
oh its not .1875? I thought that was what it was
hockeychick23
  • hockeychick23
oh its .375
UnkleRhaukus
  • UnkleRhaukus
for both right: 1/4 * 1/4 =
UnkleRhaukus
  • UnkleRhaukus
nope 0.375 is for exactly 1 right
hockeychick23
  • hockeychick23
hockeychick23
  • hockeychick23
sorry i typed it incorrectly, this is the table
UnkleRhaukus
  • UnkleRhaukus
now to be sure check the sum all the probabilities .5625 + .375 + .0625 =
hockeychick23
  • hockeychick23
.5625+.375+0.0625=1
UnkleRhaukus
  • UnkleRhaukus
Yay!
hockeychick23
  • hockeychick23
:) thanks so much!!

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