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I got: Probability of getting zero questions right by guessing: .5626(.75)= .42195 Probability of getting one question right by guessing: (0.75)(.1875)= .140625 (0.25)(.0625)= 0.015625 .140625+0.015625= .15625 but I'm not sure if i did it correctly, can someone check my answer please?
the number on the right most nodes are the total probabilities already
oh ok so the probability of getting zero right is .5625, getting one right is .25+.1875=.4375 and getting both right would be .1875?
yes the probability of getting zero right is .5625,
the probability of getting 1 right is the sum of the two probability of the nodes in the tree that are exactly 1 right ansewer
yea i got .25+.1875=.4375
ie P(1) = P(wr) + P(rw)
0.25 is the probability that the first question is right, but we want to add the probabilities that exactly one question is right
oh sorry so its .1875+.0625= .25
and then both right would be .1875
**error in diagram |dw:1433152335528:dw|
there is only one leaf on the tree that has both right answers P(rr) =
yea that leaf says .0625
i think i drew my diagram wrong when i constructed it
why do you say that? it seems right to me its multiple choice (four options) two questions
oh i just flip flopped the wrong and right on the second leaf
if we add up all the probabilities P(0) = 0.5625 P(1) = 0.1875+0.1875 = 0.3750 P(2) = 0.0625 P(0)+P(1)+P(2) = 1
wcheck that last entry in the table again
oh its not .1875? I thought that was what it was
oh its .375
for both right: 1/4 * 1/4 =
nope 0.375 is for exactly 1 right
sorry i typed it incorrectly, this is the table
now to be sure check the sum all the probabilities .5625 + .375 + .0625 =
:) thanks so much!!